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mrs_skeptik [129]
1 year ago
15

Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is divisibl

e by 3.
a. 9/30
b. 11/30
c. 1/3
Mathematics
1 answer:
MAVERICK [17]1 year ago
4 0
There are a total of 30 integers and 10 of these are divisible by 3 (3, 6, 9, 12, 15, 18, 21, 24, 27, and 30). So the probability of getting an integer divisible by 3 is \frac{10}{30} = 1/3. The answer is letter C.
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Weiming, Farhan and Sam had some comic books.
mixas84 [53]

Answer:

Farhan had 9 comic books

Sam had 51 comic books and lived in his Mother's basement

Step-by-step explanation:

W + F = 36

W = 3F

3F + F = 36

F = 9

W = 27

S + F = 60

S + 9 = 60

S = 51

5 0
1 year ago
Janelle practices basketball every afternoon in the driveway each day her goal is to make four more baskets then she made the da
Alla [95]
She made 62 baskets by day 14. 4×13=52+10=62
5 0
2 years ago
A movie theater is offering a special summer pass. Passholders pay $8 per movie for the first 5 movies and watch additional movi
Brrunno [24]
Number of movies —— C

1 —— c= 8
3——- c= 24
5—— c= 40
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3 0
1 year ago
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
2 years ago
Divide rs 350 in ratio 2:5​
mihalych1998 [28]

Answer:

100 : 250

Step-by-step explanation:

Sum the parts of the ratio, 2 + 5 = 7 parts

Divide the quantity by 7 to find the value of one part of the ratio.

350 ÷ 7 = 50 ← value of 1 part of the ratio, thus

2 parts = 2 × 50 = 100

5 parts = 5 × 50 = 250

350 = 100 : 250 in the ratio 2 : 5

6 0
1 year ago
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