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nataly862011 [7]
1 year ago
9

Solve for m: 2/5=m/70

Mathematics
2 answers:
earnstyle [38]1 year ago
7 0
multiply \space\ both \space\ sides \space\ by \space\ 70
\frac{70(2)}{5}=\frac{70m}{70}
\frac{140}{5}=1m
28=m
m=28
bekas [8.4K]1 year ago
4 0
2/5 = m / 70
cross multiply because this is a proportion
(5)(m) = (2)(70)
5m = 140
m = 140/5
m = 28 <===
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Tan 235° = 2tan20°+ tan215°​
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Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

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Hence Proved

5 0
1 year ago
Two commuters leave the same city at the same time but travel in opposite directions. One car is traveling at an average speed o
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5 hours

Step-by-step explanation:

The formula to relate speed, distance and time is:

D = V * t

Where D is the distance, V is the speed and t is the time.

As they are in opposite directions, we need to sum the speed.

So the total speed is:

V = 63 + 59 = 122 mph

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610 = 122 * t

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3 0
2 years ago
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Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .

Step-by-step explanation:

Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.

The distribution of time on social media is known to be Normal.

Let x be the number of minutes spent on social media.

Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

P(x\geq120)=1-P(x

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .

4 0
2 years ago
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