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igomit [66]
2 years ago
12

Entre Celia y Quique suman 14€. Si Celia tuviera 1 €, tendría el doble de dinero que Quique.¿ Cuanto dinero tiene cada uno?

Mathematics
2 answers:
denpristay [2]2 years ago
7 0

Answer:

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

Step-by-step explanation:

Representemos la cantidad de dinero

Celia tiene = x

Quique tiene = y

Entre Celia y Quique suman 14 €.

x + y = 14

x = 14 - y

Si Celia tuviera 1 euro, tendría el doble de dinero que Quique.

Por lo tanto,

x = 2 años

Nosotros sustituimos

2y + y = 14

3 años = 14

y = 14/3

y = 4.67 €

x = 14 € - y

x = 14 € - 4.67 €

x = 9.33 €

Por lo tanto,

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

slega [8]2 years ago
3 0

Answer:

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

Step-by-step explanation:

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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
2 years ago
Julian is using a biking app that compares his position to a simulated biker traveling Julian's target speed. When Julian is beh
Gwar [14]

Answer:

11 km/hr.

Step-by-step explanation:

Given information:

Simulated speed = 20/km/h

Time = 15 mins = 1/4 hr = 0.25 hr

Distance Covered as per simulated speed = 20\times \frac{1}{4}=5km

Position of Julian according to the app = -2\frac{1}{4}=-2.25.

Actual distance covered by the bike is

Distance= 5 - 2.25 = 2.75km

Formula for speed:

\text{Average Speed}=\frac{Distance}{Time}

\text{Average Speed}=\frac{2.75}{0.25}

\text{Average Speed}=11

Therefore, the average speed of Julian is 11 km/hr.

5 0
2 years ago
Describe how you regroup when you find the sum of 64+43
damaskus [11]
Here, regrouping is basically carrying. 

64+43 shown vertically would be:

  64
+43
-------
 107
4+3 is 7, so seven is in the ones place, but that's not the point.
60+40 is 100, so you regroup by carrying the one to the hundreds place.

Hope I helped!

5 0
2 years ago
Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi
tiny-mole [99]

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

5 0
2 years ago
What is the geometric mean of 3 and 147
Makovka662 [10]

multiply the two numbers together, then take the square root

3* 147

441

sqrt(441)

21

The geometric mean is 21

3 0
2 years ago
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