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MissTica
2 years ago
12

489 to the nearest ten​

Mathematics
2 answers:
Digiron [165]2 years ago
8 0

Answer:

490

Step-by-step explanation:

489 to the nearest ten will be the tens number approximated; 490

sammy [17]2 years ago
4 0
8 is in the tenth position.

In order to round up, the number behind it (in this case. 9) must be one of the numbers of 5-9. Because 9 meets this requirement, you can round 8 to 9 and this will make 9 to 0.

Your answer is 490
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Mr. Woo wants to ship a fishing rod to his son that is 42 inches long. He has a box that measures 10 inches by 10 inches by 40 i
chubhunter [2.5K]

Answer:

The 42 inches long fishing rod will fit in the box.

Step-by-step explanation:

The diagonal of a cuboidal box is the largest measurement inside the box.

Now, the dimensions of the box are 10 inches by 10 inches by 40 inches.

Therefore, the diagonal length of the box is \sqrt{10^{2} + 10^{2} + 40^{2}} = 42.42 inches which is greater than 42 inches.

Hence, the 42 inches long fishing rod will fit in the box. (Answer)

8 0
2 years ago
State, with an​ explanation, whether the​ mean, median, or mode gives the best description of the following average. The average
erma4kov [3.2K]

Answer:

The mean is the better method.

Step-by-step explanation:

The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.

The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.

As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.

8 0
1 year ago
For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th
Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0
2 years ago
What is the quotient (2x4 – 3x3 – 3x2 + 7x – 3) ÷ (x2 – 2x + 1)?
Bess [88]
See attached picture for answer

5 0
2 years ago
Imagine you are a financial analyst at an investment bank. According to your research of publicly-traded companies, 60% of the c
lilavasa [31]

Answer:

0.0667 = 6.67% probability that the shares of a company that fires its CEO will increase by more than 5%.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

Event A: Company fires the CEO

Event B: Shares increase by more than 5%.

Probability of a company firing it's CEO:

35% of 100 - 4 = 96%(shares did not increase by more than 5%).

60% of 4%(shared did increase by more than 5%).

So

P(A) = 0.35*0.96 + 0.6*0.04 = 0.36

Intersection of events A and B:

Fires the CEO and shared increased by more than 5%, is 60% of 4%. So

P(A \cap B) = 0.6*0.04 = 0.024

Probability that the shares of a company that fires its CEO will increase by more than 5%.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.024}{0.36} = 0.0667

0.0667 = 6.67% probability that the shares of a company that fires its CEO will increase by more than 5%.

5 0
1 year ago
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