For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th
1 answer:
Answer:
The standard deviation of the number of rushing yards for the running backs that season is 350.
Step-by-step explanation:
Consider the provided information.
The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.
Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.
Use the formula:
Here z is 2.42 and μ is 790, substitute the respective values as shown.
Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.
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Answer:
Step-by-step explanation:
Given: A graphics company charges $50 per hour to create a logo plus $250 for the ownership rights of the logo.
Let x be the number of hours , then the total cost to create the logo plus is given by :-
A private contractor charges $75 per hour to develop a logo plus a $100 supply fee.
The total cost to develop logo plus is given by :-
The equation to represent the costs would be the same is given by :_
Answer:
b) 0.0608
Step-by-step explanation:
As it is mentioned that the next two days i.e 24 hours, the probability of the rain is uniformly distributed
Therefore the rain probability is
where,
T = Length of the time interval
Plus, as we know that rain is independent
So let us assume the rain between the 8: 40 AM and 2: 35 PM on single day is P1 and the time interval is 5 hours 55 minutes
i.e
= 5.91666 hours long.
So, P1 should be
= 0.2465
Now we assume the probability of rain on day 2 is P2
So it would be same i.e 0.2465
Since these events are independent
So, the total probability is
= 0.0608
Hence, the b option is correct