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gregori [183]
2 years ago
5

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

e mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards. What is the standard deviation of the number of rushing yards for the running backs that season?
Mathematics
1 answer:
Galina-37 [17]2 years ago
4 0

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

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Erica earned a total of $50,450 last year from her two jobs. The amount she earned from her job at the store was $1,250 more tha
Mariana [72]

Erica earned a total of $50,450 last year from her two jobs. The amount she earned from her job at the store was $1,250 more than four times the amount she earned from her job at the college.

Lets x be the amount she earned from here job at college

amount she earned at the store = 4 * amount earned at college + 1250

= 4x + 1250

Amount earned at college + amount earned at store = 50450

x + 4x + 1250 = 50450

5x + 1250 = 50450

Subtract 1250 from both sides

5x = 49200 (divide by 5)

x = 9840

she earn $9840 from her job at the college

5 0
2 years ago
As a promotion, the first 50 customers who entered a certain store at a mall were asked to choose from one of two discounts. The
qaws [65]

Answer:

A) Yes, because P (F∩S) = 0

Step-by-step explanation:

Hello!

50 customers of a store were asked to choose between two discounts:

Discount 1: 20% off all purchases for the day.

Discount 2: 10% off all purchases for the week.

28 choose discount 1

22 choose discount 2

F: the selected person choose discount 1.

S: the selected person choose discount 2.

Two events are mutually exclusive when the occurrence of one of them prevents the other from occurring in one repetition of the trial and the intersection between these two events is void with zero probability of happening.

In this case, since the customers were asked to choose one out of the two events, if the customer chooses the first one, then he couldn't have chosen the second one and vice-versa. Then the intersection between these two events has zero probability, symbolically:

P(F∩S)=0

I hope it helps!

8 0
2 years ago
Sylvia invested $500 in an account compounded annually with an interest rate of 8%. Manuel invested $600 in an account with a co
Sav [38]
Syliva
T=72÷8=9 years

Manul
T=72÷7.25=9.9=10 years

Option A
8 0
2 years ago
Read 2 more answers
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1863 mailboxes t
worty [1.4K]

Answer:

3433 m²

Step-by-step explanation:

From the image, we have a rectangular box without cover and half a cylinder on top.

Formula for surface area of rectangular box with top is;

S = 2(lh + wh + lw)

From the image,

l = 0.6 m

w = 0.4 m

h = 0.55 m

Thus;

S = 2((0.6 × 0.55) + (0.4 × 0.55) + (0.6 × 0.4))

S = 1.58 m²

Now, since the top is not included for this figure, then;

Surface area of this rectangular box is;

S1 = 1.58 - (lw) = 1.58 - (0.4 × 0.6) = 1.34 m²

Surface area of a cylinder is;

S = 2πr² + 2πrh

r is radius and in this case = 0.4/2 = 0.2 m

h = 0.6

S = 2π(0.2² + (0.2 × 0.6))

S = 1.005 m²

Since it is half cylinder, then we have;

S2 = 1.005/2

S2 = 0.5025 m²

Total surface area; S_t = S1 + S2

S_t = 1.34 + 0.5025

S_t = 1.8425 m²

This is the surface area of one mail box.

Thus, for 1863 mailboxes, total surface area is;

S = 1863 × 1.8425 = 3432.5775 m²

Approximating to the nearest Sq.m gives;

S = 3433 m²

6 0
2 years ago
A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC onto ∆A′B′C′ is a followed by
Eddi Din [679]
The ABC sequence of points is clockwise in both figures, so there will be an even number of reflections or a rotation.

Rotation 90° clockwise about the point (-3, -3) would make the required transformation, but that is not an option. An equivalent is ...
   • reflection across the line x = -3
   • reflection across the line y = x
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2 years ago
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