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gregori [183]
2 years ago
5

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

e mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards. What is the standard deviation of the number of rushing yards for the running backs that season?
Mathematics
1 answer:
Galina-37 [17]2 years ago
4 0

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

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Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
1 year ago
Suppose that you were going to using the Permutation approach to see if there was a difference in the amount of money spent on c
galina1969 [7]

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Assuming null hypothesis - that there is no difference in the cell phone bills between out of state and in state.

Step-by-step explanation:

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2 years ago
Find the eccentricity, b. identify the conic, c. give an equation of the directrix, and d. sketch the conic.
densk [106]

Answer:

a) 10/3  

b) hyperbola

c) x = ± 6/5

Step-by-step explanation:

a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

r=\frac{ep}{1\pm e*cos\theta}

Given the conic equation: r=\frac{12}{3-10cos\theta}

We have to make it to be in the form r=\frac{ep}{1\pm e*cos\theta}:

r=\frac{12}{3-10cos\theta}\\\\multiply\ both\ sides\ by\ \frac{1}{3} \\\\r=\frac{12*\frac{1}{3}}{(3-10cos\theta)*\frac{1}{3}}\\\\r=\frac{12*\frac{1}{3}}{3*\frac{1}{3}-10cos\theta*\frac{1}{3}}\\\\r=\frac{4}{1-\frac{10}{3}cos\theta } \\\\r=\frac{\frac{10}{3}(\frac{6}{5} ) }{1-\frac{10}{3}cos\theta }

Comparing with  r=\frac{ep}{1\pm e*cos\theta}

e = 10/3 = 3.3333, p = 6/5

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c) The equation of the directrix is x = ±p = ± 6/5

6 0
2 years ago
the number 792 and 990, written as the product of their prime factors are 792 = 23 x 32 x 11 and 990 = 2 x 9 x 5 x 1. Hence, fin
noname [10]

Answer:

198

Step-by-step explanation:

4 0
2 years ago
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Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6
kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Step-by-step explanation:

Given : Equation  12x^3-5x=2x^2+x+6

We have to construct a  system of equations that  can be used to find the roots of the equation 12x^3-5x=2x^2+x+6

Consider the given equation 12x^3-5x=2x^2+x+6

To construct a system of equation put both sides of the given equation equal to a same variable.

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12x^3-5x=y=2x^2+x+6

Thus, The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Option (a) is correct.

   

8 0
2 years ago
Read 2 more answers
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