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Semenov [28]
2 years ago
8

Spike is not a terribly bright student. His chances of passing chemistry are 0.35; mathematics, 0.40; and both, 0.12. Are the ev

ents "Spike passes chemistry" and "Spike passes mathematics" independent? What is the probability that he fails both subjects?
Mathematics
1 answer:
Feliz [49]2 years ago
8 0

Answer:

The events "Spike passes chemistry" and "Spike passes mathematics" are not independent.

The probability that he fails both subjects = 0.37

Step-by-step explanation:

The probability of Spike passing Chemistry = P(Chemistry) = 0.35

The probability of Spike passing Mathematics = P(Mathematics) = 0.40

The probability of Spike passing both Chemistry and Mathematics = P(Chemistry,Mathematics) = 0.12

For the events "Spike passes chemistry" and "Spike passes mathematics" to be independent, P(Chemistry,Mathematics) should be equal to P(Chemistry) * P(Mathematics)

But P(Chemistry) * P(Mathematics)=0.35*0.40 =0.14

So the two events are not independent.

The Probability that he passes Chemistry or Mathematics is given by P(Chemistry) + P(Mathematics) - P(Chemistry,Mathematics)

= 0.35+0.40-0.12=0.63

So the probability that he fails both subjects is the complement of this, namely (1 - 0.63) = 0.37

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In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev
tresset_1 [31]

Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 55

95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

Using one of these points.

55 + 2sd = 62.6

2sd = 7.6

sd = 7.6/2

sd = 3.8

The standard deviation of that data set is 3.8

6 0
2 years ago
With a beginning balance of $2500 and no additional charges, there is no grace-period, you will just pay the minimum payment eac
valkas [14]

Answer:

a = $31.23 per month

b = $20.83 per month

c = 249.98 = $249.98 interest charges

                   = $624-249.98 = 374.02 profit part decrease 8% inc.                  

d = 35.35%

e = Answer is in the name; basic payment is a contract which means whilst account remains open charges are requested without fail. Should balance be less or on zero, charges are still applied.

Step-by-step explanation:

2500 x 1.2499 = interest only for start month 13 =3124.75

3124.75/ 100 x 1.08   = 8% of this = 249.98 each year.

We only have to divide each by 12 to work out monthly individual charges and subtract to find out payments.

3124.75 - 249.98 = 2874.77 = Total after charges each year.

249.98/12 = 20.83 = monthly charges.

3124.75- 2500 = 624.75 payments each year

624.75/12 = 52.06 month 1 payment before charge

52.06-20.83 =31.23 total minimum payment

2500 + 249.98

Percentage = 200:600 = 1/3 33% + (comparing to ratio 10:25 closer to 40%)

We find ratio 200:600= 33.33 + 49.995/24.75 = 2.02

33+2.02 = 35.35%

7 0
2 years ago
Will works 7 hours a day, 6 days a week.
exis [7]
A day
= £9.20x7
= £64.40

6 days
£64.40x6= £386.40

The wages he has after he shared it with his mom
£386.40/7x5
= 55.20x5
= £276

£1932/£276= 7

It will take him 7 weeks to afford a car worth £1932.
6 0
2 years ago
Gary won $70,000 in the lottery after all tax deductions. He invested part of the money at 11% and deposited the remainder in ta
Paraphin [41]
Let x represent the amount of money he invested at 11% and y money he invested at 12%. Now we write system of equations:

x*1.11 + y*1.12 = 70 000 + 7900
x + y = 70 000

We will multiply second equation with 1.11
x*1.11 + y*1.11 = 77700
and subtract if from first:
0.01*y =  200
y = 20000

x = 70000 - 20000 = 50000
6 0
2 years ago
Bud's cheeseburger and fries contained 1310 milligrams and 350 milligrams of sodium, respectively. Together they contained 66.4%
Serhud [2]

Answer:

The recommended daily intake of sodium for a 2000 calorie diet is 2500 mg.

Step-by-step explanation:

In order to calculate the daily intake of sodium we first need to calculate the mass of sodium present in both snacks, this is given by their sum.

\text{total sodium} = 1310 + 350 = 1660 \text{ mg}

We can now apply a rule of three for which the total sodium from the snacks is related to 66.4% in the same proportion as "x" mg, which is the value we want to know, is related to 100%. So we have:

\frac{1660}{x} \frac{mg}{mg} = \frac{66.4\%}{100\%}

66.4*x = 1660*100\\x = \frac{166000}{66.4} = 2500 \text{ mg}

The recommended daily intake of sodium for a 2000 calorie diet is 2500 mg.

5 0
2 years ago
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