Answer:
The anwerss to the question are
(A) P(No less than two people use their phones while driving) = 0.1225
(B) P(The probability that no more than one person of the three people use their cell phone while driving) = 0.147875
Step-by-step explanation:
The given relations are
Percentage of motorists that routinely drive while sing their phone = 35 %
The probaboloty that if a peerson is random;ty selected from a group of hudred person routinely uses their phone wjile friving P(phone) = 35
The probability that a motorist randomly selected fron a set of 100 do not routinely use thir phones while driving = P(No celll phone) = 65
Then the probability that when three people are selected at random at least two people of the three people use their cell phone while driving is
P(phone) = 35/100m = 0.35
P(No celll phone) = 65/100 = 0.65
(A) Probability of at least two of three use their phones whle driving is
0.35×0.35×0.65 +0.35×0.35×0.35 = 0.1225
(B) The probability of only one person out of three seted use their phones while driving is
(0.35)(0.65)(0.65) = 0.147875
