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2 years ago

12

You're at the aquarium, staring into a large exhibit, when you look to your left and slightly downward and you see a jellyfish.

You notice that the jellyfish body looks like a very wide, upside-down parabola. What is a possible equation that models the jellyfish, assuming your eyes are at (0, 0)?
a) -2(x + 3)2 + 4
b) -3(x - 2)2 - 1
c) -25(x + 1)2 - 5 .
d) 3(x-4)2 + 2
e) Answer is not there

1 answer:

11Alexandr11 [23.1K]2 years ago

3 0

Step-by-step explanation:

c is an upside down parabola but it is not wide, it is very then so maybe e?

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A tomato grower needs to ship early when prices are high and spoilage is low. She now has 25 tons on hand and by can add two ton

Musya8 [376]

On first week

Quantity of tomato = 25 tons

profit per ton = $250

So if she sells tomato on first week then total profit = 25 * 250 = $6250

On second week

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On third week

Quantity of tomato = 29 ton

Profit per kg = $220

So if she sells tomato on third week then total profit = 29*220 = $6380

Now consider fourth week

Quantity of tomato =31 ton

Price per kg = $205

So if she sells tomato on fourth week then total profit =31*205 = $6355

so she must ship her tomatoes on third week i.e she will attain $ 6380 as profit.

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2 years ago

1. Three friends pooled their money to purchase a new game system that costs $298. One person

iragen [17]

Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → $f+s+t=298$

Equation 2 → $s=f-9$

Equation 3 → $t=f-14$

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

$f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107$

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

$s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93$

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2 years ago

Devon exercised the same amount of time each day for 5 days last week. e His exercise included walking and swimming. e Each day

prohojiy [21]

I think that Devon swam at least 35 minutes each day for 5 days because if he exercised 225 minutes and each day he walked for 10 minutes then if you divide 225 by 5 you get 45 so every day he exercised 45 minutes and since he walked for 10 minutes you subtract 10 from 45 which gives you 35 so he swam for 35 minutes.

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2 years ago

A sociologist wishes to estimate the average number of automobile thefts in a large city per day within 2 automobiles. He wishes

anzhelika [568]

Answer:

$n=(\frac{2.58(4.2)}{2})^2 =29.35 \approx 30$

So the answer for this case would be n=30 rounded up to the nearest integer

Step-by-step explanation:

Information given

$ME = 2$ the margin of error desired

$\sigma =4.2$ standard deviation from previous studies

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance level is $\alpha=0.01$ and the critical value would be $z_{\alpha/2}=2.58$ , replacing into formula (b) we got:

$n=(\frac{2.58(4.2)}{2})^2 =29.35 \approx 30$

So the answer for this case would be n=30 rounded up to the nearest integer

5 0

2 years ago

Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is $4.6\ miles$

Part B) The length of a straight line between the school and the hospital is $2.1\ miles$

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(0,0) and C(4.3,1.7)

substitute

$d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}$

$d=\sqrt{(1.7)^{2}+(4.3)^{2}}$

$d=4.6\ miles$

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(0,0) and D(1.2,1.7)

substitute

$d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}$

$d=\sqrt{(1.7)^{2}+(1.2)^{2}}$

$d=2.1\ miles$

7 0

2 years ago