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Amiraneli [1.4K]
2 years ago
12

A company surveyed 100 newer employees. These employees were chosen at random from the company's database, and only employees wi

th less than one year on the job were selected. Employees were asked the question, "Do you want the company to offer more sick days or more vacation days?" A report of the survey results stated that employees prefer more vacation days than sick days. Select all statements that correctly evaluate the report.
A. The sample is biased because it does not represent the population of all employees.

B. The question is biased toward a response of preferring more sick days.

C. The sample is not biased.

D. The question is biased toward a response of preferring more vacation days.
E. The question is not biased.
Mathematics
1 answer:
Harman [31]2 years ago
3 0

Answer:

A, E

Step-by-step explanation:

The question is not biased.  It does not use positive or negative language.  However, the sample is biased because it only represents new employees, not the whole company.

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Each of the following phrases describes a numerical value:
DanielleElmas [232]

Answer: C

Step-by-step explanation:

The answer is C

Step-by-step explanation:

C The opposite of 9 is the same distance from 0 on a number line as the absolute value of 9.

Absolute value is the distance from zero on a number line of and number positive or negative.

7 0
1 year ago
Read 2 more answers
Consider this polynomial, where a is an unknown real number.
DENIUS [597]

Answer:

Step-by-step explanation:

Correct steps to find the value of 'a' should be,

Braulio's synthetic division should be,

-1  |     1       5         a          -3           11

   

    <u>            -1        -4        (4 - a)     (a - 1)  </u>

         1      4     (a - 4)     (1 - a)     (a + 10)

Here remainder is (a + 10).

So (a + 10) = 17 ⇒ a = 7

Braulio Incorrectly found a value of 'a' because he should have used (-1) instead of 1.

Zahra's calculation by remainder theorem should be,

p(x) = x⁴ + 5x³ + ax² - 3x + 11

p(-1) = (-1)⁴ + 5(-1)³ + a(-1)² - 3(-1) + 11

      = 1 - 5 + a + 3 + 11

      = (a + 10)

Since, remainder of the solution is 17,

(a + 10) = 17 ⇒ a = 7

Zahra incorrectly found the value of 'a' because she incorrectly solved the powers to (-1).

8 0
1 year ago
Round 287.9412 to the nearest tenth. Do not write extra zeros.
goldenfox [79]
Salutations!

<span>Round 287.9412 to the nearest tenth. 

Lets solve this!

To round to the nearest tenth, you need to know the tenth place--------

In the number, 287.9412, nine is in the tenth place. You need also make sure whether the number next to 9 is greater than 5 or not. 

</span><span>287.9412 =287.941=287.94=287.9=288=290

Thus, your answer is 290.

Hope I helped.
</span>
3 0
2 years ago
Read 2 more answers
To go on the class trip, chang needs at least $125. he has saved $45, and he makes $7 an hour at his job. what is the minimum nu
Murljashka [212]
The total amount that Chang will received from his wages is the product of his hourly wage times the number of hours he has worked (n). His total savings should not be less than $125. The equation that best describes the situation is, 
                                    45 + 7n ≥ 125
Solving for n in the inequality gives an answer of n≥11.42 hours. Thus, he needs to work for at least 12 hours.
6 0
1 year ago
Read 2 more answers
A study was performed on green sea turtles inhabiting a certain area.​ Time-depth recorders were deployed on 6 of the 76 capture
polet [3.4K]

Answer:

One can be 99% confident the true mean shell length lies within the above interval.

The population has a relative frequency distribution that is approximately normal.

Step-by-step explanation:

We are given that Time-depth recorders were deployed on 6 of the 76 captured turtles. These 6 turtles had a mean shell length of 51.3 cm and a standard deviation of 6.6 cm.  

The pivotal quantity for a 99% confidence interval for the true mean shell length is given by;

                    P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean shell length = 51.3 cm

             s = sample standard deviation = 6.6 cm

             n = sample of turtles = 6

             \mu = true mean shell length

Now, the 99% confidence interval for \mu =  \bar X \pm t_(_\frac{\alpha}{2}_)  \times \frac{s}{\sqrt{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of t at 0.5% significance level and 5 (6-1) degree of freedom is 4.032.

<u>So, 99% confidence interval for</u> \mu  =  51.3 \pm 4.032 \times \frac{6.6}{\sqrt{6} }

                                                         = [51.3 - 10.864 , 51.3 + 10.864]

                                                         = [40.44 cm, 62.16 cm]

The interpretation of the above result is that we are 99% confident that the true mean shell length lie within the above interval of [40.44 cm, 62.16 cm].

The assumption about the distribution of shell lengths must be true in order for the confidence interval, part a, to be valid is that;

C. The population has a relative frequency distribution that is approximately normal.

This assumption is reasonably satisfied as the data comes from the whole 76 turtles and also we don't know about population standard deviation.

3 0
1 year ago
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