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LUCKY_DIMON [66]
2 years ago
8

∇f = λ∇g gives us the equations 4xy = 4λx, 2x2 = 8λy. The first equation implies that x = Incorrect: Your answer is incorrect. o

r λ = Correct: Your answer is correct. .
Mathematics
1 answer:
Vlad1618 [11]2 years ago
6 0

Answer:

The answer is correct

Step-by-step explanation:

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Parallel Processing uses two or more computers, working together, to solving a problem. You connect two different computers; com
MrRissso [65]

Answer:

together rate = 1/20 min/job

one comp. rate = 1/(x-9) min/job

2nd comp. rate = 1/x min/job

-------------------------------

Equation:

rate + rate = together rate

1/x + 1/(x-9) = 1/20

---

20(x-9) + 20x = x(x-9)

40x-9*20 = x^2-9x

---

x^2-49x + 180 = 0

Factor:

(x-45)(x-4) = 0

Realistic solution since 4-9 is negative:

x = 45 minutes

then

x-9 = 36 minutes (faster computer time to do the job)

Step-by-step explanation:

8 0
2 years ago
In measuring reaction time, a psychologist estimates that a standard deviation is .05 seconds. How large a sample of measurement
blondinia [14]

Answer:

97

Step-by-step explanation:

We are asked to find the size of sample to be 95% confident that the error in psychologist estimate of mean reaction time will not exceed 0.01 seconds.

We will use following formula to solve our given problem.

n\geq (\frac{z_{\alpha/2}\cdot\sigma}{E})^2, where,

\sigma=\text{Standard deviation}=0.05,

\alpha=\text{Significance level}=1-0.95=0.05,

z_{\alpha/2}=\text{Critical value}=z_{0.025}=1.96.

E=\text{Margin of error}

n=\text{Sample size}

Substitute given values:

n\geq (\frac{z_{0.025}\cdot\sigma}{E})^2

n\geq (\frac{1.96\cdot0.05}{0.01})^2

n\geq (\frac{0.098}{0.01})^2

n\geq (9.8)^2

n\geq 96.04

Therefore, the sample size must be 97 in order to be 95% confident that the error in his estimate of mean reaction time will not exceed 0.01 seconds.

5 0
2 years ago
Determine whether the value given below is from a discrete or continuous data set. The volume of cola in a can is 11.1 oz. nothi
mars1129 [50]

Answer:

The given variable is a continuous variable.

Step-by-step explanation:

We are given the following variable in the question:

Variable: "The volume of cola in a can is 11.1 oz"

Discrete variable:

  • These can be expressed in whole numbers and cannot take value in decimals
  • They are counted not measured.
  • They cannot take any value within an interval.

Continuous Variable:

  • These can be expressed in decimal numbers.
  • They are measured not counted.
  • They can take any value within an interval.

Thus, the given variable which is volume is measured and can tale any value within an interval.

Thus, it is a continuous variable.

3 0
2 years ago
The menu price of a sandwich at a restaurant is $6. The purchase is subject to a 5% food tax, and you would like to leave a tip
Leya [2.2K]

Answer: See explanation

Step-by-step explanation:

Price of sandwich = $6

Food tax = 5% of $6

= 0.05 × $6

= $0.3

Tip = 20% of $6

= 0.2 × $6

= $1.2

Total cost of meal:

= $6 + $0.3 + $1.2

= $7.5

3 0
2 years ago
Read 2 more answers
The time it takes to transmit a file always depends on the file size. Suppose you transmitted 30 files, with the average size of
Ostrovityanka [42]

Answer:

Y = 0.009042 + 0.0002457X

Y = 0.1073 seconds

Step-by-step explanation:

In the given problem we have two variables: the transmission time and average size of file.

Y = transmission time

X = average file size

The linear regression model is given by

Y = a + bX

The slope b is given by

b = correlation coefficient*(SDy/SDx)

Where SDy is the standard deviation of average transmittance time and SDx is the standard deviation of average file size.

b = 0.86(0.01/35)

b = 0.0002457

The y-intercept a is given by

a = y - bx

a =  0.04 - (0.0002457)126

a = 0.04 - 0.030958

a = 0.009042

Therefore, the linear regression model is

Y = 0.009042 + 0.0002457X

Predict the time it will take to transmit a 400 Kbyte file.

Substitute X = 400 in the regression model

Y = 0.009042 + 0.0002457(400)

Y = 0.009042 + 0.09828

Y = 0.1073 seconds

Therefore, the predicted time to transmit a 400 Kbyte file is 0.1073 seconds.

8 0
2 years ago
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