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NeX [460]
2 years ago
14

Dr. Mitchell, an animal veterinarian, collected data during animal examinations on the kind of animal a boy or girl has as a pet

. Based on the data collected, which statement is true?
Mathematics
2 answers:
CaHeK987 [17]2 years ago
8 0

Can you plz show us the data collected.

Naily [24]2 years ago
4 0

Answer:

Dr. Mitchell, an animal veterinarian, collected data during animal examinations on the kind of animal a boy or girl has as a pet. Based on the data collected, which statement is true?

A) A girl is 17% more likely than a boy to own a cat than a dog or other animal.  

B) A girl is 45% more likely than a boy to own a cat than a dog or other animal.  

C) A girl is 29% more likely than a boy to own a cat than a dog or other animal.  

D) A girl is 67% more likely than a boy to own a cat than a dog or other animal.  

Step-by-step explanation:

Boy Girl

Dog    27  18

Cat    15  25

Other 10  12

hope this helps.

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A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
Suppose that lower production costs increases the supply of wheat, such that more wheat is supplied at each price level. After t
just olya [345]

When the demand and supply curve intersect, that is, where the quantity demanded and quantity supplied are equal, the market is said to be in equilibrium. Thus, the given quantity is equilibrium quantity.

From the graph, we see that when the production cost of wheat is $4, the equilibrium quantity is 600 units.

When the production cost lowers from $4 to $3, the supply of wheat increases, such that the equilibrium quantity increases from 600 units to 800 units.

Thus, after an increase in supply, the equilibrium quantity increases.

So, Option A is the correct answer.

3 0
2 years ago
Read 2 more answers
Patient A receives 3 times the amount of a certain medication as Patient B. The two doses add to 200 milligrams. What amount of
EastWind [94]

Answer:

Patient A - 150 mg

Patient B - 50 mg

Step-by-step explanation:

Since patient A gets three times more, 50 times 3 is 150. 150 plus 50 is 200, therefore, patient A gets 150 mg and patient B gets 50 mg. I hope this helps :)

5 0
1 year ago
On her first day in a hospital, Kiri receives u1 milligrams (mg) of a therapeutic drug. The amount of the drug Kiri receives inc
Valentin [98]

Answer:

a. 21 = u1 + 6·d

b. 29 = u1 + 10·d

c. d = 2, u1 = 9

Step-by-step explanation:

a. The given parameters are;

The amount of therapeutic drug Kiri receives on her first at the hospital = u1 milligrams

The amount of drug increase received by Kiri each day = d

The amount of drug Kiri received on the seventh day = 21 mg

The amount of drug she received on the eleventh day = 29 mg

Therefore, we have an arithmetic progression with the formula for the nth term given as follows;

aₙ = a₁ + (n - 1)·d

Where;

a₁ = u1

n = The number of terms

Therefore, for the 7th day, the amount of drugs she receives, which is 21 milligrams, is given as follows;

a₇ = u1 + (7 - 1)·d = u1 + 6·d = 21

The equation for the amount of drugs she receives in terms of u1 and d on the seventh day is given as follows;

21 = u1 + 6·d

b. For the eleventh day, the amount of drugs she receives, which is 29 milligrams, is given as follows;

a₁₁ = u1 + (11 - 1)·d = u1 + 10·d = 29

Therefore, the equation for the amount of drugs she receives in terms of u1 and d on the  eleventh day is given as follows;

29 = u1 + 10·d

c. Therefore, we have two equations which are given as follows;

21 = u1 + 6·d................(1)

29 = u1 + 10·d..............(2)

Subtracting equation (1) from equation (2) gives;

29 - 21 = (u1 + 10·d) - (u1 + 6·d)

8 = 4·d

d = 8/4 = 2

d = 2

From equation (1), we have;

21 = u1 + 6·d = u1 + 6×2 = u1 + 12

21 = u1 + 12

21 - 12 = u1

∴ u1 = 9

d = 2, u1 = 9.

4 0
1 year ago
The horsepower , H(s), required for a racecar to overcome wind resistance is given by the function : H(s) = 0.003s^2+0.07s-0.027
mote1985 [20]
Average rate of change = [H(100) - H(80)] / (100 - 80)
H(100) = 0.003(100)^2 + 0.07(100) - 0.027 = 0.003(10000) + 0.07(100) - 0.027 = 30 + 7 - 0.027 = 36.973

H(80) = 0.003(80)^2 + 0.07(80) - 0.027 = 0.003(6400) + 0.07(80) - 0.027 = 19.2 + 5.6 - 0.027 = 24.773

Average rate of change = (36.973 - 24.773)/(100 - 80) = 12.2/20 = 0.61

Answer: B
8 0
2 years ago
Read 2 more answers
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