Answer:
1/5
Step-by-step explanation:
∑ from 1 to infinity of 12(3/5)^(i - 1)
Since the common ratio is less than 1, the series is convegent. [i.e. 3/5 < 1]
Sum to infinity of a geometric series is given by a/(1 - r); where a is the first term, and r is the common ratio.
Sum = 12/(1 - 3/5) = 12/(2/5) = 30.
Answer:
All the expressions other than option E, is equivalent to the expression 18m - 12.
Step-by-step explanation:
A. 6m - 4 + 6m -4 + 6m - 4
or 6m+6m+6m -4 -4 -4
or 18m -12
B. 12m + 6 - 6m -6
or 12m - 6m + 6 - 6
or 6m
C.6(3m - 2)
or 18m - 12
D.3(6m - 4)
or 18m - 12
E. 24n - 4² + 8 -6m
This option can not satisfy the given expression as it contains another variable as n.
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:
Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
Two consecutive numbers can be defined as x and y, but a better choice is x and x+1. . The product of the two numbers is: x(x+1). We are told this 41 more than the sum. The sum of the two numbers is: x + (x+1). . So the equation we need to solve is: . x(x+1) = x+(x+1)+41 . x^2 +x = 2x + 42 . subtract 2x from both sides . x^2 +x -2x = 2x-2x + 42 x^2 -x = 42 . subtract 42 from both sides . x^2 -x -42 = 42-42 = 0
