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ddd [48]
1 year ago
13

ABC is translated 6 units up and 3 units left to crest A’B’C’. If vertex A is at (-1,2) and vertex B is at (1, 5) then vertex A’

is at (5, 1) or (-4, 8) and vertex B’ is at (-2, 11) or (-7, -1).
Mathematics
1 answer:
jekas [21]1 year ago
3 0

The translation is

... (x, y) ⇒ (x -3, y +6) . . . . . 3 units left, 6 units up

Then

... A(-1, 2) ⇒ A'(-1-3, 2+6) = A'(-4, 8)

... B(1, 5) ⇒ B'(1 -3, 5 +6) = B'(-2, 11)

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Two functions are defined as shown. f(x) =-1/2 x – 2 g(x) = –1 Which graph shows the input value for which f(x) = g(x)?
Natalka [10]

Answer:

See attachment.

Step-by-step explanation:

The given functions are:

f(x) =  -  \frac{1}{2}x - 2

and g(x)=-1

To find the x-value of the point of intersection of the two functions, we equate the two functions and solve for x.

-  \frac{1}{2}x - 2 = -1

x + 4 = 2

x = 2 - 4 =  - 2

The graph that shows the input value for which f(x)=g(x) is the graph which shows the point of intersection of f(x) and g(x) to be at x=-2.

4 0
2 years ago
Read 2 more answers
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
Lucy ate eight more than three times as many pretzels as Matt Lucy ate 56 pretzels how many pretzels did Matt eat
mr_godi [17]

Answer:

53

Step-by-step explanation:

56-3

5 0
2 years ago
People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the
Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by  

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0
2 years ago
At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. The bicyclist head
7nadin3 [17]
Let x be the rate of the slower bicyclist and
      x + 4 be the rate of the faster bicyclist

Since the bicyclists are headed towards opposite directions, the sum of the distances they covered traveling for one hour and 15 minutes should be equal to 40 km based on the given conditions above. This may be expressed as,
 
                                   (x)(1.25) + (x + 4)(1.25) = 40

Calculating gives x = 14 

Thus, the rate of the bicyclists are 14 km/h and 18 km/h.
3 0
1 year ago
Read 2 more answers
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