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ddd [48]
2 years ago
13

ABC is translated 6 units up and 3 units left to crest A’B’C’. If vertex A is at (-1,2) and vertex B is at (1, 5) then vertex A’

is at (5, 1) or (-4, 8) and vertex B’ is at (-2, 11) or (-7, -1).
Mathematics
1 answer:
jekas [21]2 years ago
3 0

The translation is

... (x, y) ⇒ (x -3, y +6) . . . . . 3 units left, 6 units up

Then

... A(-1, 2) ⇒ A'(-1-3, 2+6) = A'(-4, 8)

... B(1, 5) ⇒ B'(1 -3, 5 +6) = B'(-2, 11)

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How much would Carol have to invest today at 6.2% compounded annually to have $4600 for a vacation to China in two years?
KiRa [710]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4600\\
P=\textit{original amount deposited}\\
r=rate\to 6.2\%\to \frac{6.2}{100}\to &0.062\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, so once}
\end{array}\to &1\\

t=years\to &2
\end{cases}
\\\\\\
4600=P\left(1+\frac{0.062}{1}\right)^{1\cdot 2}

solve for P
5 0
2 years ago
Suppose a marketing company computed a 94% confidence interval for the true proportion of customers who click on ads on their sm
Ksivusya [100]

Answer:

d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.

Step-by-step explanation:

Confidence interval:

x% confidence

Of a sample

Between a and b.

Interpretation: We are x% sure(or there is a x% probability/chance) that the population mean is between a and b.

In this question:

I suppose(due to the options) there was a small typing mistake, and we have a 98% confidence interval between 0.56 and 0.62.

Interpreation: We are 98% sure, or there is a 98% chance, that the true population proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. Option d.

3 0
2 years ago
tony goes to the funfair and has one go on the hoopla ad one go on the darts. the probability that he wins at hoopla is 0.3 the
frez [133]

Answer:

Step-by-step explanation:

4 0
2 years ago
Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen
Anna007 [38]

Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Convert mixed fractions into improper fractions:

4\frac{1}{2}\Rightarrow \frac{9}{2}

2\frac{1}{4}\Rightarrow \frac{9}{4}

\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}

Using property \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}:

\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}

\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}

We know that distance is equal to the product of speed and time.

\text{Distance}=\text{Speed}\times\text{Time}

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}

\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}

\text{Distance covered by Jingua on return trip}=5\text{ Miles}

Therefore, Jingua hiked 5 miles on her return trip.

8 0
2 years ago
Write the ratio as a fraction in simplest form: 2.35 to 5.25.
Sliva [168]

Step-by-step explanation:

\frac{2.35}{5.25}  =  \frac{235}{525}  =  \frac{47}{105}  = 47 \:  : \: 105 \\

4 0
2 years ago
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