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Lesechka [4]
1 year ago
6

harry buys 22 fish he has a round fish bowl and a rectangular fish tank how could he place the fish in the bowl and tank

Mathematics
1 answer:
Lana71 [14]1 year ago
6 0

Answer: put 11 in each one


Step-by-step explanation:


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Darcie wants to crochet a minimum of 3 blankets blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a
bearhunter [10]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal is:

s\leq 15

Thus, Darcie can skip a maximum of 15 days.

Step-by-step explanation:

Question

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Given:

Darcie has a target to crochet a minimum of 3 blankets.

Rate at which Darcie crochets = \frac{1}{15} of a blanket per day.

Darcie has 60 days to crochet the blankets

To write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

The number of days Darcie can skip crocheting is represented by s

So, number of days left for Darcie to crochet = 60-s

In 1 day Darcie crochets  \frac{1}{15} of a blanket.

So, in (60-s) days she will crochet = \frac{1}{15}(60-s)  blankets.

Her aim is to crochet at least 3 blankets.

Thus, the inequality can be given as:

\frac{1}{15}(60-s)\geq 3

Solving for s

Multiplying both sides by 15 to remove fractions.

15\times\frac{1}{15}(60-s)\geq 3\times 15

60-s\geq 45

Subtracting both sides by 60.

60-60-s\geq 45-60

-s\geq -15

Dividing both sides by -1.

\frac{-s}{-1}\leq \frac{-15}{-1}     [ On dividing by negative number the sign of the inequality is reversed]

∴ s\leq 15

Thus, Darcie can skip a maximum of 15 days.

3 0
1 year ago
Read 2 more answers
Drag each interval to a box to show if the function shown is increasing, decreasing, or neither over that interval.
prisoha [69]

Answer:

Increasing

−5<x<−1

−1<x<1

Decreasing

4<x<7

−8<x<−5

Neither Increasing nor Decreasing

1<x<4

Step-by-step explanation:

8 0
1 year ago
Read 2 more answers
Your utility company charges 13 cents per kilowatt-hour of electricity. What is the daily cost of keeping lit a 75 watt light bu
Tresset [83]

we know that

1 Kw=1000 w

The company charges 13 cents per kilowatt-hour of electricity

13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw

Step 1

Find the cost for the light bulb

a) in one day

\frac{75}{1000} *12=0.9\ kw\  hour

Cost=0.13*0.9

Cost=$0.117

b) In a year

\frac{75}{1000} *12=0.9\ kw\  hour

0.9*365=328.5\ kw\  hour

Cost=0.13*328.5

Cost=$42.71

Step 2

Find the cost for the led bulb

a) in one day

\frac{15}{1000} *12=0.18\ kw\  hour

Cost=0.13*0.18

Cost=$0.0234

b) In a year

\frac{15}{1000} *12=0.18\ kw\  hour

0.18*365=65.7\ kw\  hour

Cost=0.13*65.7

Cost=$8.54

Step 3

Find the difference in cost

Save=42.71-8.54\\ Save=34.17 dollars

therefore

the answer is

34.17 dollars

3 0
2 years ago
Read 2 more answers
Describe in words the surface whose equation is given. (assume that r is not negative.) θ = π/4
Delvig [45]
An equation in the form \theta=\dfrac{\pi}{4} is the line 
that goes through the origins and whose tangent equates \dfrac{\pi}{4}. In general, any equation in the form \theta=\theta_0
is the equation of a line. 
7 0
2 years ago
An oblique prism has trapezoidal bases and a vertical height of 10 units. An oblique trapezoidal prism is shown. The trapezoid h
denis23 [38]

Answer:

volume of trapezoidal prism = 15x^2 cubic units

Step-by-step explanation:

First, area of the trapezoidal bases.

Parallel sides measure x and 2x, for an average of 1.5x.

Height = x

Area of trapezoidal base = 1.5x*x = 1.5x^2

Volume of prism = area base * height

(length does not matter, height does)

= 1.5x^2 * 10 = 15x^2

5 0
1 year ago
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