Question

A person has to walk 100 m to go from position X in the north of east direction to the position B and then to the west of Y to reach finally at position Z. The position Z is situated at the north of X and at a distance of 60 m from X. Find the distance between X and Y.

Answer 1

Answer:

The distance between X and Y is 68m

Step-by-step explanation:

Consider the diagram attached:

A person starts from X, goes to Y, and then finally goes to Z, covering a total of 100m, where Z is located 60m in north of X.

We have to find distance XY.

Let the distance XY be x

Total distance covered by the person = XY + YZ

We know that total distance covered is 100m, so

100m = x + YZ

YZ = (100 - x)m

See the diagram, XZY forms a right angled triangle such that:

Hypotenuse = XY = x

Base = XZ = 60m

Perpendicular = YZ = (100-x)m

Using Pythagoras theorem

Hypotenuse² = Base² + Perpendicular²

x² = (60)² + (100-x)²

Solve the equation for x, we get:

x = 68m