Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.
1-9 = 9 digits
10-99 = 180 digits
So if we continue the pattern to 99, there are 189 digits, and the last 5 digits would be 79899. Counting backwards: 189th = 9, 188th = 9, 187th = 8, 186th = 9, 185th = 7.
The 185th digit is 7.
30 choices
The Roberts family is shopping for a new car. They are considering a minivan or an SUV. Those vehicles come in red, gold, green, silver, or blue. Each vehicle has three models; standard (S), sport (P), or luxury (L). Use the tree diagram to answer the question.
Answer:
The number of large size candles sells are 12 and the number of small size candles are 5 .
Step-by-step explanation:
As given
Sia sells large candles for $3 each and small candles for $2 each.
She sold 17 candles for $46.00.
Let us assume that the large size candle sells are x .
Let us assume that the small size candle sells are y.
Equation becomes
x + y = 17
3x + 2y = 46
Multiply x + y = 17 by 3 and subtracted from 3x + 2y = 46 .
3x - 3x + 2y - 3y = 46 - 51
-y = - 5
y = 5
Put in the equation x + y = 17 .
x + 5 = 17
x = 17 - 5
x = 12
Therefore the number of large size candles sells are 12 and the number of small size candles are 5 .
Answer:
Sarah multiplied the denominator by the denominator and the numerator by the numerator instead of finding the cross products. The equation should be 5x = 42, so the cost should be $8.40.
Step-by-step explanation:
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