Answer:
[0.4235, 0.5365]
Step-by-step explanation:
Data given and notation
n=300 represent the random sample taken
X=300-98-58=144 represent the people that support the candidate A in the sample
estimated proportion of people that support the candidate A in the sample
represent the significance level
Confidence =0.95 or 95%
p= population proportion of people that support the candidate A.
Confidence interval
The confidence interval would be given by this formula
For the 95% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution.
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.4235;0.5365).
Answer:
Given:
Body mass index values:
17.7
29.4
19.2
27.5
33.5
25.6
22.1
44.9
26.5
18.3
22.4
32.4
24.9
28.6
37.7
26.1
21.8
21.2
30.7
21.4
Constructing a frequency distribution beginning with a lower class limit of 15.0 and use a class width of 6.0.
we have:
Body Mass Index____ Frequency
15.0 - 20.9__________3( values of 17.7, 18.3, & 19.2 are within this range)
21.0 to 26.9__________8 values are within this range)
27.0 - 32.9____________ 5 values
33.0 - 38.9____________ 2 values
39.0 - 44.9 _____________2 values
The frequency distribution is not a normal distribution. Here, although the frequencies start from the lowest, increases afterwards and then a decrease is recorded again, it is not normally distributed because it is not symmetric.
Answer: P(hist& french)=16/200=0.08
Step-by-step explanation:
To find the required probability we have to know what is the number of students that take both History and French ( Intersection of 2 circles in Venn diagram)
1. Lets find the number of students that take History or French or both.
We know that 8% from 200 take neither History or French. So number or students who take History or French or both is 200-200*0.08=184
2. Let number of students that takes French (or both Fr+Hist)=x (left circle)
So number of students that takes History (or both Fr+Hist)=4x (right circle)
So number of students that take both French+History= 10% from 4x or
0.1*4x=0.4x (circles' intersection)
3. Now we have the equation as follows:
x+4*x-0.4*x = 184
4.6*x=184
x=40 students takes French (or both French+ History)
4*x= 40*4=160 students takes History (or both French+ History)
10% from 160 =0.1*160=16 students takes both History and French
P(hist& french)=16/200=0.08
Answer:
1184000
Step-by-step explanation:
lcm(2960,6400,2000)
prime factor:
Take the largest power of each factor:
