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alina1380 [7]
2 years ago
15

Sia sells large candles for $3 each and small candles for $2 each. She sold 17 candles for $46.00. How many of each size candle

did she sell?
Mathematics
1 answer:
kipiarov [429]2 years ago
8 0

Answer:

The number of large size candles sells are 12 and the number of small size candles are 5 .

Step-by-step explanation:

As given

Sia sells large candles for $3 each and small candles for $2 each.

She sold 17 candles for $46.00.

Let us assume that the large size candle sells are x .

Let us assume that the small size candle sells are y.

Equation becomes

x + y = 17

3x + 2y = 46

Multiply x + y = 17 by 3 and subtracted from 3x + 2y = 46 .

3x - 3x + 2y - 3y = 46 - 51

-y = - 5

y = 5

Put in the equation x + y = 17 .

x + 5 = 17

x = 17 - 5

x = 12

Therefore the number of large size candles sells are 12 and the number of small size candles are 5 .

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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

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How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
2 years ago
In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? AB ≅
siniylev [52]

For any quadrilateral to be a parallelogram

i) either both the pairs of opposite sides must be equal

ii) Both the pairs of opposite sides must be parallel

iii) Opposite pairs of angles must be equal

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v) A pair of opposite sides must be parallel and equal

Here we are already given that AB || CD

So either we should be given that AD || BC

or we must be given that AB = CD

Here it is given AB = CD as an option.

So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.


7 0
2 years ago
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Dima020 [189]

Answer:

225.5

Step-by-step explanation:

So, you would start by doing

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Then you would add

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2 years ago
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stepan [7]

Answer:

3

Step-by-step explanation:

i had it

4 0
2 years ago
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A book costs d dollars.
bazaltina [42]

Answer:

The total amount paid by Jill  = $ (3 d)

Step-by-step explanation:

Here, the cost of 1 book = $ d

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So, the total cost of 3 books  = 3 x ( Cost of 1 book)

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So, if Jill purchased 3 books, the total amount paid by her = $ (3 d)

3 0
1 year ago
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