Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
-0.5, 2, 4.5, 7, 9.5
Step-by-step explanation:
The given terms are 6 apart, so the common difference is 1/6 of their difference:
d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5
Add 2.5 to each term to get the next one. Then the sequence is ...
-3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12
9.2 x 13.8 = 126.96, now usually to get the area of a triangle we would half this but because we have two of the same triangle we would then have to double it again so they cancel each other out. We then do 6.9 x 9.2 which equals 63.48 and again we have two of the same triangle so no need to half it. So we add the two totals of 126.96 and 63.48 together to get 190.44.
Answer:
<DFE is congruent to <GFH
Step-by-step explanation:
you need an angle to prove SAS and <DFE is congruent to <GFH