A robot moves 3\text{ m}3 m3, start text, space, m, end text, turns more than 90\degree90°90, degree clockwise, moves 4\text{ m}
4 m4, start text, space, m, end text more, turns clockwise again, then moves 3.6\,\text{m}3.6m3, point, 6, start text, m, end text. The robot ends where it started, as shown.
How far did the robot turn the first time?
Do not round during your calculations. Round your final answer to the nearest degree.
How far did the robot turn the first time?
Do not round during your calculations. Round your final answer to the nearest degree.
2 answers:
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Answer:
A.) Acceleration = 4.6 m/s^2
B.) Average speed = 47 m/s
Step-by-step explanation:
A.) From the graph, at t = 10s,
Velocity V = 46 m/s
Acceleration a = (change in V)/ time t
a = (46 - 0)/10
a = 46/10 = 4.6 m/s^2
B.) If we estimate the speed at 5 seconds intervals, then we have
Average speed = (36 + 46 + 49 + 50 + 50 +50 + 50) ÷ 7
Average speed = 331/7 = 47.29 m/s
Average speed = 47 m/s
