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lara31 [8.8K]
2 years ago
7

Solve for the equation -2y+y-3 = 6

Mathematics
1 answer:
pashok25 [27]2 years ago
7 0

Answer: y = -9

Step-by-step explanation:

(-2y) + y - 3 = 6

(-y) - 3 = 6

-y = 9

y = -9

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Match each concept with its key characteristic.
Crank

1. It is the subset of a group  - Group sample.

2. It equally favors all members of a group sample   - Random sample.

3. It collects data on members of a group  -  Survey.

4. It does not equally favor all members of a group - Biased sample.

5. It includes all members of a group   -  Population.

6. It analyzes data collected from a group - Mean.


I have matched all concepts in accordance with statistical use, hope it helps.


6 0
2 years ago
A theatre ticket costs £63 plus a booking fee of 3% what is the total cost of the ticket
Genrish500 [490]

Answer:

64.89 is the total cost

Step-by-step explanation:

63 x .03 = 1.89

63 + 1.89 = 64.89

5 0
2 years ago
Read 2 more answers
Kyle asks his friend Jane to guess his age and his grandmother’s age. Kyle says his grandmother is not more than 80 years old. H
melamori03 [73]
#1 is incorrect. The first equation says that his grandmother is not more than 80 years old. If you confine yourself to whole numbers, then she could be 80 but not more. That inequality should be written as g < 81 or if you are a purist, g≤ 80. 

The second equation is correct. At the very most her age is equal to 3k - 3 so at most it would be written as g = 3k - 3.

Since it is not that much, you would write it as g ≤ 3k - 3
6 0
2 years ago
Read 2 more answers
A country's population in 1993 was 94 million. in 1999 in was 99 million. estimate the population in 2005 using the exponential
Jet001 [13]
The initial population is
P₀ = 94 million in 1993

The growth formula is
P(t) = P_{0}e^{kt}
where P(t) is the population (in millions) after t years, measured from 1993.
k = constant.

Because P(5) = 99 million (in 1999), 
94e^{5k} = 99 \\e^{5k}=1.0532 \\ 5k = ln(1.0532) \\ k = 0.010367

In the year 2005, t = 12 years, and
P(12)=94e^{0.010367*12} = 106.45

Answer: 106 million (nearest million)

7 0
1 year ago
A mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. Th
Arturiano [62]

Answer:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of  hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

P(x\geq 1)=1-P(x=0)       .... (1)

According to binomial expression

P(x=r)=^nC_rp^rq^{n-r}

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

P(x=0)=^6C_0(0.10)^0(0.90)^{6-0}

P(x=0)=0.531441

Substitute the value of P(x=0) in (1).

P(x\geq 1)=1-0.531441

P(x\geq 1)=0.468559

P(x\geq 1)\approx 0.469

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

3 0
1 year ago
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