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2 years ago

Solve for the equation -2y+y-3 = 6

Mathematics

1 answer:

pashok25 [27]2 years ago

7 0

Answer: y = -9

Step-by-step explanation:

(-2y) + y - 3 = 6

(-y) - 3 = 6

-y = 9

y = -9

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Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?

maks197457 [2]

Answer:

1) x³-y³ = (x-y)(x²-xy+y²)

2)x²-y² =(x-y)(x+y)

3)x-y = (x-y)

hcf = (x-y)

lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)

Step-by-step explanation:

5 0

2 years ago

1) A 1.5 kg apple pie is sitting on the kitchen counter . If it has 13.44 J of gravitational potential energy, how tall is the c

vampirchik [111]

Answer: 0.91 m

Explanation:

We know that,

P.E. = m g h

Where,

P.E = Potential energy

m = Mass of the object

g = acceleration due to gravity (9.8 m/s²)

It is given that, m = 1.5 kg

P.E. = 13.44 J

⇒ 13.44 = 1.5 kg × 9.8 m/s² × h

⇒ h = 0.91 m

Hence, apple sits om 0.91 m tall counter.

Answer: 216 J

Explanation:

P.E. = m g h

Weight, mg = 120 N ( given)

height, h = 1.8 m ( given)

The energy possessed by the suitcase is due to virtue of its position (gravitational potential energy)

P.E. = 120 N × 1.8 m = 216 J

Hence, the energy possessed by the suitcase sitting on the counter is 216 J.

8 0

2 years ago

Which function grows at the fastest rate for increasing values of x? h(x)=2x f(x)=8x2−3x g(x)=19x p(x)=5x3+3

Nesterboy [21]

G(x)=19x is the function that’ll grow at the fastest rate.

5 0

2 years ago

Mr. Donley drove 504 km in each direction on a vacation

mestny [16]

Answer:

Data that we know:

He drove 504km in each direction.

Going, the average speed was 14km/h more than returning.

The total trip lasted 21 hours.

Ok, to solve this first:

Let's define the variables:

Sg = Average speed when going.

Sr = Average speed when returning.

Then we can write one of our relationships as:

Sg = Sr + 14km/h.

Now, you can recall the relation:

Time = Distance/speed.

Then we can write the equation that represents the total time of the travel as:

504km/Sg + 504km/Sr = 21h

Now we can replace the Sg by Sr + 14km/h, and get:

504km/(Sr + 14km/h) + 504km/Sr = 21h.

Now we must multiplacate by each denominator, in order to remove them:

504km*Sr + 504km*(Sr + 14km/h) = 21h*Sr*(Sr + 14km/h)

Sr*1008km + 7056km^2/h = 21h*Sr^2 + 294km*Sr

Now we can write a cuadratic equation, where i will ignore the units so it is easier to read, as:

21*Sr^2 -714*Sr - 7056 = 0

The solutions are given by the Bhaskara formula:

$Sr = \frac{714 +- \sqrt{714^2 - 4*21*(-7056)} }{2*21} = \frac{714 +- 1050}{42}$

We have two solutions, one negative and one positive, and because Sr represents an average speed, it must be a positive number, then we choose the positive solution:

Sr = (714 + 1050)/42 km/h = 42km/h

Now we have the average speed for the returning, with this we can find Sg.

Sg = Sr + 14km/h = 42km/h + 14km/h = 56km/h.

6 0

2 years ago

What is y={-\dfrac{1}{3}}x-9y=− 3 1 x−9y, equals, minus, start fraction, 1, divided by, 3, end fraction, x, minus, 9 written i

Kobotan [32]

Answer:

$x+3y=-27$

Step-by-step explanation:

We are given that

$y=(-\frac{1}{3})x-9$

We have to find the standard form of given equation

$y=\frac{-x-27}{3}$

$3y=-x-27$

By using multiplication property of equality

$x+3y=-27$

We know that

Standard form of equation

$ax+by=c$

Therefore, the standard form of given equation is given by

$x+3y=-27$

5 0

2 years ago