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Gnesinka [82]
2 years ago
12

Find the volume of the rectangular prism.

Mathematics
2 answers:
sp2606 [1]2 years ago
4 0
Hey there!! :D




I believe the answer is D. 576 cm3









Glad I Could Be Of An Assistance










Please Correct Me If I Am Incorrect :P
















My Apologies Are Given :D








Hope this helps!!







Have A Marvelous Friday!!




Have An Outstanding Weekend!!








Bond [772]2 years ago
3 0
The equation for the volume of a rectangular prism is:
V = lwh
where V = volume, l = length of base, w = width of base, and h = height of the prism.

From your picture, you can see that the length, l = 16cm, width, w = 9cm, and the height of the prism, h = 4cm. Plug these numbers into the equation and solve for volume:
V = lwh\\
V = (16\:cm)(9\:cm)(4\:cm)\\
V = 576 \: cm^3

--------

Answer: D) 576 cm^3
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Answer:

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Step-by-step explanation:

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  W = (P/2) -L

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Answer:

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

\hat p=\frac{67}{150}=0.447 estimated proportion of applicants who request financial aid

p_o=0.35 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

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2 years ago
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