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2 years ago

7

A group of astronomers observed light coming from a star located a distance of 331,000,000,000,000,000,000,000,000 light-years f

rom Earth. What is this distance expressed in scientific notation?

2 answers:

Nikitich [7]2 years ago

8 0

3.31 x 10^26 im pretty sure

Anika [276]2 years ago

5 0

3.31 times 10 to the 26th power

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It takes Daphne 25 minutes to assemble a model plane. During her work day Daphne takes 30 minutes for lunch and one 15 minute br

natka813 [3]

Answer:

<h2>y=25p-45</h2>

Step-by-step explanation:

We first of all start by cumulating all the time she spent for break

lunch= 30min

break= 15min

total break= 45min

also the time taken to assemble one model plane 25min

let the number of hours be p

and the total number of model plane be y

The model is

y=25p-45

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2 years ago

Round to the nearest benchmark fraction 5/9

Stells [14]

1/2 because 5/9 is equivalent to 10/18. Half of 18 is 9 and 10 is close to 9 so the nearest benchmark fraction you should round to is 1/2. Hope this helps you!

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2 years ago

After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum

Svetlanka [38]

Answer: 40000

Step-by-step explanation:

The formula to find the sample size is given by :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$ , where p is the prior estimate of the population proportion.

Here we can see that the sample size is inversely proportion withe square of margin of error.

i.e. $n\ \alpha\ \dfrac{1}{E^2}$

By the equation inverse variation, we have

$n_1E_1^2=n_2E_2^2$

Given : $E_1=0.05$ $n_1=1000$

$E_2=0.025$

Then, we have

$(1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000$

Hence, the sample size will now have to be 4000.

6 0

1 year ago

Thrice of product of five and b is reduced by 2

Diano4ka-milaya [45]

3 times the product of 5 and b is reduced by 2
3*(5*b)-2
15b-2

5 0

2 years ago

In circle N, KL ≅ ML. Circle N is shown. Line segments N J, N M, N L, and N K are radii. Lines are drawn to connect each point o

Sergeu [11.5K]

Answer:

$arc\ JM=132^o$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

we know that

$arc\ JM+arc\ ML+arc\ LK+arc\ KJ=360^o$ ----> by complete circle

substitute the given values

$(13x+2)^o+(8x-3)^o+(7x+7)^o+(5x+24)^o=360^o$

solve for x

$(33x+30)^o=360^o\\33x=360-30\\33x=330\\x=10$

step 2

Find the measure of arc JM

$arc\ JM=(13x+2)^o$

substitute the value of x

$arc\ JM=(13(10)+2)^o=132^o$

8 0

2 years ago

Read 2 more answers