at what x coordinate would a line whose equation is y=2x-3 intersect a perpendicular line whose y intercept is 17

Which expression is equivalent to -9x^-1y^-9/-15x^5y^-3? Assume x is not equal to 0,y is not equal to 0

VladimirAG [237]

I am going to assume that "v" is meant to be a "y"
the answer is b. (3)/(5x^6 y^6)

7 0

1 year ago

Lilly and Alex went to a Mexican restaurant. Lilly paid $9 for 2 tacos and 3 enchiladas, and Alex paid $12.50 for 3 tacos and 4

Tema [17]

Let's call Tacos t and Enchiladas e.
Lily paid $9 for 2t and 3e
Alex paid $12.50 for 3t and 4e.
Thus the equations would be.
$2t + 3e = 9.00$
$3t + 4e = 12.50$

4 0

2 years ago

Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord

andrew-mc [135]

Consider the circle with center X, as shown in the figure.

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is

$\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8$ units.

Answer: 8 units

7 0

2 years ago

What is the balance on an amortized loan of $110,000 after the first payment if the interest rate is 5.5% with a monthly P&I

marishachu [46]

The interest due on the first payment is
.. I = Prt
.. I = 110,000*.055*(1/12)
.. I = 504.17

Then the decrease in principal resulting from the first payment is
.. 568.00 -504.17 = 63.83
and the new balance is
.. $110,000.00 -63.83 = $109,936.17

4 0

2 years ago

Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate

mars1129 [50]

Answer: In the beginning he was given 27 sweets.

Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.

On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;

8/a = 2/3

By cross multiplication we now have

8 x 3 = 2a

24/2 = a

a = 12

Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;

12/b = 2/3

By cross multiplication we now have

12 x 3 = 2b

36 = 2b

36/2 = b

b = 18

Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;

18/x = 2/3

By cross multiplication we now have

18 x 3 = 2x

54 = 2x

x = 27

Therefore Tim was given 27 sweets at the beginning.

3 0

2 years ago

at what x coordinate would a line whose equation is y=2x-3 intersect a perpendicular line whose y intercept is 17​

at what x coordinate would a line whose equation is y=2x-3 intersect a perpendicular line whose y intercept is 17