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zimovet [89]
2 years ago
12

Alberto conducted an experiment by rolling a fair six-sided number cube 60 times. He rolled a 2 fifteen times. Which statement a

bout rolling a 2 in Alberto’s experiment is correct?
The experimental probability of rolling a 2 is One-third and the theoretical probability of rolling a 2 is One-fourth.

The experimental probability of rolling a 2 is One-fourth and the theoretical probability of rolling a 2 is One-third.

The experimental probability of rolling a 2 is One-fourth and the theoretical probability of rolling a 2 is One-sixth.

The experimental probability of rolling a 2 is One-sixth and the theoretical probability of rolling a 2 is One-fourth.
Mathematics
2 answers:
Olenka [21]2 years ago
6 0

Answer:

the third answer

Step-by-step explanation:

ya gurl got 100 on the test e d g e n u i t y

VladimirAG [237]2 years ago
4 0

Answer:

Third one:

The experimental probability of rolling a 2 is One-fourth and the theoretical probability of rolling a 2 is One-sixth.

Step-by-step explanation:

Theoretical probability of 2:

1/6

Experimental probability of 2:

15/60 = 1/4

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Three students solve a challenge math problem. Every day, the number of students who solve the problem doubles. There are 384 st
attashe74 [19]

OK, so this is assuming we are considering that the first three kids to solve ARE NOT in the first day.


So we have 3 kids and it doubles

Day 1 : 6

Day 2 : 12

Day 3 : 24

Day 4 : 48

Day 5 : 96

Day 6 : 192

Day 7: 384


So it should take 7 days or a week to solve all the problems.

The equation:

(3 * 2)^x = 384


8 0
1 year ago
Read 2 more answers
During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str
Brilliant_brown [7]

Answer:

number of successes

                 k  =  235

number of failure

                 y  = 265

The   criteria are met    

A

    The sample proportion is  \r p  =  0.47

B

    E =4.4 \%

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from  the true population proportion will not  more than 4.4%

Ci  

   r =  0.514 = 51.4 \%

 v =  0.426 =  42.6 \%

D

   This 95% confidence interval  mean that the the chance of the true    population proportion of those that are happy to be exist within the upper   and the lower limit  is  95%

E

  Given that 50% of the population proportion  lie with the 95% confidence interval  the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

 Yes our result would support the claim because

            \frac{1}{3 } \ of  N    < \frac{1}{2}  (50\%) \ of \  N  , \ Where\ N \ is \ the \  population\ size

Step-by-step explanation:

From the question we are told that

     The sample size is  n  = 500

     The sample proportion is  \r p  =  0.47

 

Generally the number of successes is mathematical represented as

             k  =  n  *  \r p

substituting values

             k  =  500 * 0.47

            k  =  235

Generally the number of failure  is mathematical represented as

           y  =  n  *  (1 -\r p )

substituting values

           y  =  500  *  (1 - 0.47  )

           y  = 265

for approximate normality for a confidence interval  criteria to be satisfied

          np > 5  \ and  \ n(1- p ) \ >5

Given that the above is true for this survey then we can say that the criteria are met

  Given that the confidence level is  95%  then the level of confidence is mathematically evaluated as

                       \alpha  = 100 - 95

                        \alpha  = 5 \%

                        \alpha  =0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is

                 Z_{\frac{ \alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

                E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{\r p (1- \r p}{n} }

substituting values

                 E =  1.96 *  \sqrt{ \frac{0.47 (1- 0.47}{500} }

                 E = 0.044

=>               E =4.4 \%

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from  the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

          \r p  - E <  p  <  \r p  + E

substituting values

        0.47 -  0.044 <  p  < 0.47 +  0.044

         0.426 <  p  < 0.514

The upper limit of the 95% confidence interval is  r =  0.514 = 51.4 \%

The lower limit of the   95% confidence interval is  v =  0.426 =  42.6 \%

This 95% confidence interval  mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit  is  95%

Given that 50% of the population proportion  lie with the 95% confidence interval  the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

            \frac{1}{3 }  < \frac{1}{2}  (50\%)

 

3 0
2 years ago
Which equation has the components of 0 = x2 – 9x – 20 inserted into the quadratic formula correctly? x = x = x = x =
Ber [7]
To solve the quadratic equation given by 0=x^2-9x-20, we use the quadratic formula given by:
x=[-b+\- sqrt(b^2-4ac)]/(2a)
where,
a=1,b=-9,c=-20
thus substituting the above values into our formula we get:
x=[9+\-sqrt(9^2-4(-20*1))/(2*1)
x=[9+\-sqrt(161)]/2
x=[9+sqrt161]/2 or x=[9-sqrt161]/2
6 0
2 years ago
Read 2 more answers
In a café, drinks are priced according to what size they are.
Andrei [34K]
A) Gavin’s drinks altogether cost £9.00
1.50+2.50x3
=1.50+7.50
=£9.00
b) Lian gets back £3.50
1.50+2.00+3.00
=6.50

10.00-6.50=£3.50
8 0
2 years ago
he following data set shows the number of dogs counted in a local park each Saturday for 4 months. 33, 36, 31, 37, 37, 38, 31, 3
lana66690 [7]

General Idea:

To create a dot plot for a set of data we should list the data from lowest to greatest number. Then create a number line which covers all the numbers given in the data. We need to plot number of circles one above as many times based on the frequency of the data.

Applying the concept:

33, 36, 31, 37, 37, 38, 31, 37, 35, 31, 38, 32, 36, 33, 38

Listing the data in ascending order we get

31, 31, 31, 32, 33, 33, 35, 36, 36, 37, 37, 37, 38, 38, 38

We need to plot <u>three </u>circles above 31, <u>one</u> circle above 32, <u>two</u> circles above 33, <u>one</u> above 35, <u>two </u>above 36, <u>three </u>above 37, and <u>three</u> above 38.

Conclusion:

Out of the four options, the <u>correct option is B </u>because that is the only dot plot representing the given set of data.

7 0
2 years ago
Read 2 more answers
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