Given functin is :
![f\left(x\right)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3D%5Csqrt%5B5%5D%7Bx%7D)
We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.
Domain: (-∞,∞)
Range is the set of y-values obtained by plugging values from domain so the range will also same.
Range: (-∞,∞)
If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.
It crosses x and y-axes both at the origin
Hence x-intercept=0 and y-intercept=0
Graph is not symmetric about y-axis hence it can't be EVEN
Graph is not symmetric about origin so it is ODD.
There is no breaking point in the graph so that means it is a Continuous function.
There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.
END behaviour means how y-changes when x approaches infinity.
From graph we can see that when x-approaches -∞ then y also approaches ∞.
when x-approaches +∞ then y also approaches +∞.
5d + 2(2 - d) = 3(1 + d) + 1
5d + 2(2) - 2(d) = 3(1) + 3(d) + 1
5d + 4 - 2d = 3 + 3d + 1
5d - 2d + 4 = 3d + 3 + 1
3d + 4 = 3d + 4
<u>-3d -3d </u>
4 = 4
d = 0
Hi there, I believe the answer is 20. Because, each corner is 4 chairs plus every two feet, equals 20. Hope this helps!
Answer:
The height of the tower is 130.5m
Step-by-step explanation:
In the question, we are given the following values:
The angles of elevation to the top of the tower from P = 50°
The angles of elevation to the top of the tower from Q = 45°
The angles of elevation to the top of the tower from P = 50°
Hence,cot P = 1/ tan(50°)
The angles of elevation to the top of the tower from Q = 45°
Hence, tan 45° = 1
In the question,we are told Points P and Q lie 240 m apart in line with and on opposite sides of a communications tower.
Therefore,
PQ = height of the tower( tan Q + 1/tan P)
240m = height of the tower( tan 45° + 1/ tan 50°)
240m = h(1 + 1/tan 50°)
h = (240 m)/(1 + 1/tan (50°))
h = 130.49863962 meters
Therefore, the height of the tower to the nearest tenth of a meter is 130.5 meters(m)