Answer:
18, 21, 36
Step-by-step explanation:
Let L represent the least number. Then the greatest is 2L and the middle number is (L+3). Their sum is ...
L +(2L) +(L+3) = 75
4L = 72 . . . . . . . . . subtract 2, collect terms
L = 18 . . . . . . . . . . . divide by 4
L+3 = 21
2L = 36
The numbers are 18, 21, and 36.
Answer:
2.6779*10^5
Step-by-step explanation:
The problem given is 2.69*10^5 - 1.21*10^3 which is 269000-1210=267790 -> 2.6779*10^5
Answer:
55
Step-by-step explanation:
412.5 / 7.5 =55
The left hand side expression of the given equation is a difference of two squares. The first term, x², is a square of x and the second term, 25 is the square of 5. The factors of the expression are (x - 5) and (x + 5).
(x - 5)(x + 5) = 0
The values of x from the equation above are x = -5 and x = 5.
Answer: at 11:54
Step-by-step explanation:
Let's define the 10:30 as our t = 0 min.
We know that Train A stops every 12 mins, and Train B stops every 14 mins, they will stop at the same time in the least common multiple of 12 and 14.
To find the least common multiple of two numbers, we must do:
LCM(a,b) = a*b/GCD(a,b)
Where GCD(a, b) is the greatest common divisor of a and b.
In this case the only common divisior of 12 and 14 is 2.
So we have:
LCM(12, 14) = 12*14/2 = 84.
Then the both trains will stop 84 minutes after 10:30
one hour has 60 mins, so we can write 84 minutes as:
1 hour and 24 minutes = 1:24
Then they will stop at the same time at 10:30 + 1:24 = 11:54