Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Answer:
0.32km
Step-by-step explanation:
The speed that a tsunami can travel is modeled by the equation s = 356 StartRoot d EndRoot , where S is the speed in kilometers per hour and d is the average depth of the water in kilometers.
This is written mathematically as:
S = 356√d
What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?
S = 200km/hr
Hence:
200km/hr = 356√d
Divide both sides by 356
200/356 = 356√d/356
√d = 200/356
Square both sides
(√d)² = (200/356)²
d =(0.5617977528)²
d = 0.3156167151km
Approximately = 0.32km
Answer:
$15.8666666667 an hour on average
Step-by-step explanation:
14/7.5=1.8666666666
this means that for every hour the proofreader is working he proof reads 1.8666667 pages since he makes 8.5 for every page we have to multiply the pages per hour times the salary of every page to get his average hourly wage
1.8666666666 * 8.5 = $15.8666666667 an hour on average
Answer:
Step-by-step explanation:
a) sum of angle on the straight line TRW is 180.
Given <TRS = 2x+10
<SRW = x-10
<TRS+<SRW = 180
2x+10+x-10 = 180
3x = 180
x = 180/3
x = 60°
<TRV = 180°-(2x+10)
Substitute x = 60° into the expression
<TRV = 180-(2(60)+10)
<TRV = 180-(120+10)
<TRV = 180-130
<TRV = 50°
2) From the diagram attached <MHJ= <LHK (oppositely directed angle)
Given
<MHJ= x+15
<LHK = 2x-20
Substitute the given data into the formula to get x
x+15= 2x-20
x-2x = -15-20
-x = -35
x = 35°
Next is to get the measure of <MHJ
<MHJ = x+15
<MHJ = 35+15
<MHJ = 50°
Answer:
2.5 dB/100 ft
Explanation:
If 5 dB was lost after 200 ft of cable and 100 ft is half of 200 ft, then the rate of loss should be 2.5 dB per 100 ft.
Step-by-step explanation:
