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jek_recluse [69]
2 years ago
12

If 1134 bricks are used to build a wall that is 18ft long, how high is the wall?

Mathematics
1 answer:
Trava [24]2 years ago
6 0
Need some more info, what are the dimensions of the bricks?

You might be interested in
R+5/mn=p solve for m
AnnZ [28]

Answer:

               \bold{m\ =\ \dfrac5{(p-r)n}}

Step-by-step explanation:

                                             \bold{r+\dfrac5{mn}\ =\ p}\\\\ {}\quad-r\qquad-r\\\\{}\ \ \bold{\dfrac5{mn}\ =\ p-r}\\\\{}\ ^{_\times}(mn)\quad ^{_\times}(mn)\\\\{}\quad\bold{5\ =\ (p-r)^{_\times}(mn)}\\\\\div(p-r)\quad\div(p-r)\\\\{}\ \ \bold{\dfrac5{p-r}\ =\ mn}\\\\{}\quad \ \div n\quad\ \ \div n\\\\\bold{\dfrac5{(p-r)n}\ =\ m}

If you mean (r+5)/mn then:

\bold{\dfrac{r+5}{mn}\ =\ p}\\\\{}\ ^{_\times}(mn)\quad ^{_\times}(mn)\\\\{}\ \bold{r+5\ =\ pmn}\\\\\div(pn)\quad\div(pn)\\\\{}\ \ \bold{\dfrac{r+5}{pn}\ =\ m}

4 0
2 years ago
Talulah is an ecologist who studies the change in the penguin population of Antarctica over time. She observed that the populati
Oksana_A [137]

Answer:

P(t) = 27000 * (1/9)^(t/4)

Step-by-step explanation:

This problem can me modelled with an exponencial formula:

P = Po * (1+r)^t

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In this problem, we have that the inicial population/value is 27000, the rate is -8/9 (negative because the population decays), and the time t is in months, so as the rate is for every 4 months, we use the value (t/4) in the exponencial.

So, our function will be:

P(t) = 27000 * (1-8/9)^(t/4)

P(t) = 27000 * (1/9)^(t/4)

8 0
2 years ago
Read 2 more answers
For a data set of weights​ (pounds) and highway fuel consumption amounts​ (mpg) of seven types of​ automobile, the linear correl
ololo11 [35]

Answer:

The​ P-value indicates that the probability of a linear correlation coefficient that is at least as extreme is__3.5%___ which is___significant_(at α=0.05)_ so there _is_ sufficient evidence to conclude that there is a linear correlation between weight and highway fuel consumption in automobiles.

Step-by-step explanation:

Correlation coefficient shows the relation between the <em>weights</em><em>​</em> and <em>highway fuel consumption amounts</em> of seven types of automobile.

P-value states <em>the significance</em> of this relationship. If the p-value is lower than a <em>significance level</em> (for example 0.05) then the relation is said to be significant.

5 0
2 years ago
What values of c and d make the equation true? RootIndex 3 StartRoot 162 x Superscript c Baseline y Superscript 5 Baseline EndRo
Reil [10]

Answer:

<em>c=6, d=2</em>

Step-by-step explanation:

<em>Equations </em>

We must find the values of c and d that make the below equation be true

\sqrt[3]{162x^cy^5}=3x^2y \sqrt[3]{6y^d}

Let's cube both sides of the equation:

\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3

The left side just simplifies the cubic root with the cube:

162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3

On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

162x^cy^5=3^3x^6y^3 (6y^d)

Simplifying

x^cy^5=x^6y^{3+d}

Equating the powers of x and y separately we find

c=6

5=3+d

d=2

The values are

\boxed{c=6,d=2}

3 0
2 years ago
Read 2 more answers
A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
stealth61 [152]

Answer:

a) 0.954

b) 0.937

c) 0.891  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  6 percent

Standard Deviation, σ = 1.3 percent

We are given that the distribution of particular interest rate is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(At least 3.8 percent.)

P(x \geq 3.8)

P( x \geq 3.8) = P( z \geq \displaystyle\frac{3.8 - 6}{1.3}) = P(z > -1.69)

= 1 - P(z < -1.69)

Calculation the value from standard normal z table, we have,  

P(x \geq 3.8) = 1 - 0.046 = 0.954 = 95.4\%

b) P(At most 8 percent)

P(x \leq 8) = P(z \leq \displaystyle\frac{8-6}{1.3}) = P(z \leq 1.53)

Calculating the value from the standard normal table we have,

P( x \leq 8) =0.937= 93.7\%

c) P(Between 3.8 percent and 8 percent. )

P(3.8 \leq x \leq 8) = P(-1.69 \leq z \leq 1.53)\\\\= P(z \leq 1.53) - P(z < -1.69)\\= 0.937 - 0.046 = 0.891 = 89.1\%

P(3.8 \leq x \leq 8) = 89.1\%

3 0
2 years ago
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