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STatiana [176]
1 year ago
9

Lisa says that the indicated angles cannot have the same measure. Marita disagrees and says she can prove that they can have the

same measure. Who do you agree with? Justify your answer.
Equations: (9x - 25 + x)°
(x + 50 + 2x - 12)°






HELP ASAP :D
Mathematics
1 answer:
AlexFokin [52]1 year ago
8 0
I agree with Marita, that the angles could have the same measure.  This can be proven if you set the two amounts equal and solve for x. 

9x - 25 + x = x + 50 + 2x - 12

To begin, we should combine like terms on both sides of the equation to start simplifying the equation.

10x - 25 = 3x + 38

Next, we should subtract 3x from both sides and add 25 to both sides to get the variable x alone on the left side of the equation.

7x = 63

Finally, we should divide both sides by 7, to get rid of the coefficient of x.

x = 9

If you plug in 9 for x in our first equation, you get that both of the angle measurements equal 65 degrees.  This means that Marita is correct, because if x = 9, then the angles would have the same measure.


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A boat on the ocean is 2 mi from the nearest point on a straight? shoreline; that point is 15 mi from a restaurant on the shore.
Sladkaya [172]

Answer:

a) x  =  0,70 miles

T  =  1/2* (√4 + x²)  +( 15 - x )/3   Objective Function to minimize

b) V(min)  = 2.59 m/hr

Step-by-step explanation:

Let assume the boat is in Point A,  she lands in point B, and R  is the restaurant

Let call  x distance between the point O in  which perpendicular line from the boat get to shoreline, and the point were she land.

We know  distance is

d = v*t       ⇒  t = d/v

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According to that she takes

c (hypotenuse) of right triangle  AOB/ 2 rowing

and  15 - x /3  walking

Total time is:

T  =  c/2  + ( 15-x )/3          c =√(2)² + x²     ⇒  T = [√(2)² + x²  ] /2  +  ( 15-x )/3  

T  =  1/2* (√4 + x²)  +( 15 - x )/3   (1)

And that is  the Objective function to minimize

a) Taking derivatives on both sides of the equation we get

T´(t)  =  x /( √4 + x²)  - 1/3    ⇒   T´(t)  = 0     x /( √4 + x²)  - 1/3 = 0

3*x - √( √4 + x²) = 0     ⇒  3*x  =  √( √4 + x²)

Squaring both sides

9x²  =  4 + x²     ⇒  8x²  = 4       x² = 1/2      x  =  0,70 miles

If we plug this value in the Objective function we will get the minimum time

1/2* (√4 + x²)  +( 15 - x )/3    ⇒ [√ 4  + 0,5] /2 +  14,3/3 = T (min)

T(min)  =  1.06 + 4.77  = 5.83 hr

Distance L (hypotenuse of right triangle AOR)

L = √(2)²  + (15)²   L  = 15,13 miles

And that distance have to be traveled at least in 5.83 hr rowing

Then  as  v = d/t      V(min)  =  15.13/ 5.83   ⇒    V(min)  = 2.59 m/hr

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2 years ago
Chandresh is helping his father paint the fence in their back yard. The fence is represented by the shaded part of the diagram b
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B. The total area painted is 864; they must buy two cans of paint.

Step-by-step explanation:

Step 1:

A rectangle's area can be calculated by multiplying its length and its width. The wall is made up of 5 different types of rectangular walls. All walls are 8 feet tall but the length varies.

Step 2:

The area of the 20 feet long wall = (length)(width)= (20)(8) =160,

The area of the 10 feet long wall = (length)(width)= (10)(8) =80,

The area of the 5 feet long wall = (length)(width)= (5)(8) =40,

The area of the 4 feet long wall = (length)(width)= (4)(8) =32,

The area of the 15 feet long wall = (length)(width)= (15)(8) =120.

The area of all the walls = 432 square feet.

Since there are two sides for every wall, total area = 432(2)=864 square feet.

Step 3:

If one paint can covers 500 square feet,

the number of cans required to paint 864 square feet = \frac{864}{500} = 1.728 cans.

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Answer:

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Step-by-step explanation:

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In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

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e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

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