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Ahat [919]
2 years ago
7

Ephemeral services corporation (esco) knows that nine other companies besides esco are bidding for a $900,000 government contrac

t. each company has an equal chance of being awarded the contract. if esco has already spent $100,000 in developing its bidding proposal, what is its expected net profit?
a. $10,000

b. $0

c. $100,000

d. $90,000
Mathematics
1 answer:
EastWind [94]2 years ago
4 0

Answer:

c. $100,000

Step-by-step explanation:

Calculation of the expected net profit of Ephemeral services corporation

Since we are been told that 9 other companies besides esco are as well bidding for the $900,000 government contract, it means we have to find the expected net profit by dividing 1 by 9×$900,000 .Thus ESCO can only expect to cover its sunk cost.

Hence ,

E(X) = (1/9) × $900,000

E(X)=0.111111111×$900,000

E(X)= $100,000

Therefore the expected net profit would be $100,000

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These tables represent a quadratic function with a vertex at (0,3) What us the average rate of change from the interval from x=7
VladimirAG [237]
The rate of change is shown to the right of the second graph as being -2 

At 5 to 6 the average rate of change is -11, so at 6 to 7 the rate of change would be -11-2 = -13, then from 7 to 8 it would be -13-2 = -15.

The answer is D. -15
3 0
1 year ago
Chuck has a gross pay of $815.70. By how much will Chuck’s gross pay be reduced if he has the following items withheld?
Alex787 [66]

Answer:

273.38

Step-by-step explanation:

815.70 * 6.2% = 50.57

815.70 * 1.45% = 11.83

815.70 * 19% = 154.95

Add those 3 totals to the additional $56 in federal tax

56+50.57+11.83+154.95 = 273.35

5 0
2 years ago
Read 2 more answers
Theresa has hired Chuck and Diana to paint a fence. Diana can paint 150 fence posts in the same time it takes Chuck to paint 130
Alenkasestr [34]

Answer: Chuck can paint 65 posts per hour.

Step-by-step explanation:

The data we have here is:

Diana can paint 150 fence posts in a time T

Chuck can pint 130 fence posts in a time T.

In one hour, Diana can paint 10 more fence posts than Chuck.

If D is the hourly rate of Daian, and C is the hourly rate for Chuck, we have:

D = 150/T

C = 130/T

D = C + 10

we can replace the last equation in the first one and geT:

C + 10 =150/T

C = 130/T

Now we can replace the bottom equation in the above one:

130/T + 10 = 150/T

10 = 150/T - 130/T =  20/T

T*10 = 20

T = 20/10 = 2

So T is 2 hours, then whe have:

D = 150post/2hours = 75 posts per hour.

C = 130 posts/2hours = 65 posts per hour.

4 0
2 years ago
Is it possible to form a triangle with side lengths 3.5 3.5, and 9? If so, will it be scalene, isosceles, or equilateral? Or non
Charra [1.4K]

Answer:

It is not possible to draw a triangle with given measurements of 3.5, 3.5, and 9.

Step-by-step explanation:

<em><u>Scalene Triangle</u></em> - All 3 sides have different lengths.

<em><u>I</u></em><em><u>s</u></em><em><u>osceles</u></em><em><u> </u></em><em><u>Triangle</u></em> - 2 sides have equal lengths.

<em><u>Equilateral</u></em><em><u> </u></em><em><u>Triangle</u></em> - All 3 sides have equal lengths.

You must be thinking that it would be Isosceles triangle, but it is not. The measurements you gave is 3.5, 3.5, and 9. Grab a piece of paper, ruler, and a pencil. First draw the length of 9 cm with your pencil and ruler (let us pretend that the measurements are in cm). Then draw 3.5 cm by placing your ruler on the end/start of your 9cm line that you drew before. Then, once again draw a 3.5 cm on the other end of the 9cm line. You will see something like the picture above. You can see that the two sides of the triangle are not intersecting on the top. This means that the triangle formation cannot be made by the given measurements of 3.5, 3.5, and 9.

I hope you understand my answer and this is an easy way to find if, from the given measurements, a triangle is able to be drawn. Thank you !!

4 0
1 year ago
The length of time a full length movie runs from opening to credits is normally distributed with a mean of 1.9 hours and standar
Llana [10]

Answer:

a) The probability that a random movie is between 1.8 and 2.0 hours = 0.2586.

b) The probability that a random movie is longer than 2.3 hours is 0.0918.

c) The length of movie that is shorter than 94% of the movies is 1.4 hours

Step-by-step explanation:

In the above question, we would solve it using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation

a) A random movie is between 1.8 and 2.0 hours

z = (x-μ)/σ,

x1 = 1.8,

x2 = 2.0

μ is the population mean = 1.9

σ is the population standard deviation = 0.3

z1 = (1.8 - 1.9)/0.3

z1 = -1/0.3

z1 = -0.33333

Using the z score table

P(z1 = -0.33) = 0.3707

z2 = (2.0 - 1.9)/0.3

z1 = 1/0.3

z1 = 0.33333

p(z2 = 0.33) = 0.6293

= P(- 0.33 ≤ z ≤ 0.33)

= 0.6293 - 0.3707

= 0.2586

The probability that a random movie is between 1.8 and 2.0 hours = 0.2586

b) A movie is longer than 2.3 hours

z = (x-μ)/σ,

x1 = 2.3

μ is the population mean = 1.9

σ is the population standard deviation = 0.3

z = (2.3 - 1.9)/0.3

z = 4/0.3

z = 1.33333

P(z = 1.33) = 0.90824

P(x>2.3) = = 1 - 0.90824

= 0.091759

≈ 0.0918

The probability that a random movie is longer than 2.3 hours is 0.0918.

3) The length of movie that is shorter than 94% of the movies.

z = (x-μ)/σ

Probability (z ) = 94% = 0.94

Movie that is shorter than 0.94

= P(1 - 0.94) = P(0.06)

Finding the P (x< 0.06) = -1.555

≈ -1.56

μ is the population mean = 1.9

σ is the population standard deviation = 0.3

-1.56 = (x - 1.9)/ 0.3

Cross multiply

-1.56 × 0.3 = x - 1.9

- 0.468 + 1.9 = x

= 1.432 hours

≈ 1.4 hours

Therefore, the length of movie that is shorter than 94% of the movies is 1.4 hours

5 0
1 year ago
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