Answer:
The square root of terms separated by addition and subtraction cannot be calculated individually.
Step-by-step explanation:
In order to calculate the square root, we would need a monomial or a factored expression. We do not have that, so we cannot take the square root.
-115
Using the arithmetic formula, your equation appears as so:
an = 15 + (27 - 1) - 5
15 being the first number in the sequence, 27 being the number you're trying to find, and -5 being the common difference.
This will give you the answer of -115.
Hope this helps!
Answer:
i know im vv late but i dont want anyone to get it wrong. anyway if your on e2020 i believe the correct answer is
D. The company cannot provide lunch for all 20 employees and use the entire budget because there is no solution to the system of equations mc019-r+t=20 and 5r+5t=150
Step-by-step explanation:
Answer:
(B)93
Explanation:
Since we are using a fixed-order-interval model,
The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand
Where:
d=weekly demand
OI=Order Interval
LT=Lead Time
z=Standard Deviation of Desired Service Level
=Standard Deviation of weekly Demand
A= Amount at Hand
![[30(3 + 1)] + [1.964*4*\sqrt{3 + 1} - 43](https://tex.z-dn.net/?f=%20%5B30%283%20%2B%201%29%5D%20%2B%20%5B1.964%2A4%2A%5Csqrt%7B3%20%2B%201%7D%20-%2043)
To solve this problem, we can use the z statistic to find
for the probability. The formula for z score is:
z = (x – u) / s
Where,
u = the sample mean = 68
s = standard deviation of the samples = 12
x = sample value = 70
In this case, what is asked is the probability that the
sample mean is larger than 70, therefore this corresponds to the right of z on
the graph of normal distribution.
z = (70 – 68) / 12
z = 2 / 12
z = 0.17
Therefore finding for P at z ≥ 0.17 using the standard
distribution tables:
P (z = 0.17) = 0.5675
But this is not the answer yet since this is the P to the
left of z. Therefore the correct one is:
P (z ≥ 0.17) = 1 - 0.5675
P (z ≥ 0.17) = 0.4325 = 43.25%
<span>The probability that the sample mean is larger than 70 is
43.25%</span>
