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Tatiana [17]
2 years ago
14

The perimeter of a square is 80-64y units. Which expression can be used to show the side length of one side of the square?

Mathematics
2 answers:
nalin [4]2 years ago
8 0
I think it’s 20-16y :)
Darya [45]2 years ago
6 0

Answer:

it is 20-16y

Step-by-step explanation:

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The equations below represent the numbers y of tickets sold after x weeks for two different local music festivals
Anton [14]
Assuming you mean y=10x+150 and y=20x+115, you need to use a simultaneous equation, because you have two equations with two unknowns (x and y)

rearrange so
10x-y=-150
20x-y=-115

multiply the top by -1, so that if we add the two lines together, the y will cancel out
-10x+y=150
20x-y=-115

add the two lines together
10x=35
x=3.5

so the time is 3 and a half weeks

then we can sub in x to find y
20x-y=-115
20(3.5)-y=-115
70-y=-115
-y=-185
y=185

so 185 tickets were sold !
you can sub these values into your original equations to check your answer :)
5 0
2 years ago
Read 2 more answers
Train A traveled 173 miles in five hours. For Train B, y = 31.35x represents its rate of speed over the same five hours. Which t
kap26 [50]
<span> D) Train A by a factor of 1.1
</span>Train A: <span>17/35</span><span> = 34.6</span>

<span>Train B: </span>Rate<span> is the </span>slope<span> of the </span>equation, 31.35

Thus,<span>34.6/31.35</span><span> = 1.1036</span>
4 0
2 years ago
Read 2 more answers
Adult male heights have a normal probability distribution with a mean of 70 inches and a standard deviation of 4 inches. What is
NNADVOKAT [17]

Answer:

The probability that the man is greater than 74 inches is 0.1587

Step-by-step explanation:

The required probability is found by evaluating the area under the corresponding distribution curve for the corresponding values

The standard normal variate factor (Z) is given by

Z=\frac{x-\bar {X}}{\sigma }

where

\bar{x} is mean of the data

\sigma is the standard deviation of the data

Thus corresponding to x = 74 the Z factor equals

Z=\frac{74-70}{4}=1

Using the standard normal distribution table corresponding to mean of 70 and deviation of 4 the area under the curve corresponding to Z = 1 equals

0.1587

6 0
2 years ago
Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from​ B, a distance o
g100num [7]

Answer:

The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

   The distance from city A to B is   AB =  467.3 miles

   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

     \theta_B  =  32^o

and  

      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

Also  

    \frac{CA}{sin (32)} =  \frac{467.3 }{sin (107.8)}

    CA = 260 .1 \ miles

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct​ flight is mathematically represented as

      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

=>  k =109.6 \ miles

4 0
2 years ago
A marble is selected at random from a jar containing 3 red​ marbles, 4 yellow​ marbles, and 6 green marbles. What is the probabi
alexgriva [62]

Answer:  a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

​a) the marble is​ red? ​

Probability of getting a red marble = \dfrac{3}{13}

b) the marble is not​ yellow?

Probability of not getting yellow = \dfrac{3+6}{13}=\dfrac{9}{13}

​c) the marble is either red or ​green?

Probability of getting either red or green = P(red) + P(green) =\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}

d) the marble is neither red nor ​green?

Probability of getting neither red nor green = P(getting yellow) = \dfrac{4}{13}

Hence, a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

5 0
2 years ago
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