Answer:
the complete question is found in the attachment
1) D. hyperbolic paraboloid
2)C. elliptic paraboloid
3)E. cone
4)F. hyperboloid.
Step-by-step explanation:
The complete explanation is found in the attachment
We can start solving this problem by first identifying what the elements of the sets really are.
R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.
Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).
W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.
W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.
R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.
0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.
∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are <u>not</u> an element of R).
{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be <u>equal</u> to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).
-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
Answer: $680.00
Step-by-step explanation:
Principal= 8500
Rate= 4%
Time= 2 years
Interest= (Principal×Rate×Time)/100
= (8500×4×2)/100
= 68000/100
= $680
The interest is $680
This part of the plane is a triangle. Call it
. We can find the intercepts by setting two variables to 0 simultaneously; we'd find, for instance, that
means
, so that (4, 0, 0) is one vertex of the triangle. Similarly, we'd find that (0, 5, 0) and (0, 0, 20) are the other two vertices.
Next, we can parameterize the surface by
so that the surface element is
Then the area of
is given by the surface integral
