Finding the slope of both coordinates, you'll get 15/2. The slopes are the same
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.
Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit.
Let s represent scarves and h represent hats.
10s + 20h <u>></u> 300
s + h <u>></u> 20
We use inequality because the problem states "at least".
s + h = 20
10s + 20h = 300
s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10
s = 20 - h
s = 20 - 10
s = 10
s + h <u>></u> 20
10 + 10 <u>></u> 20
10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300
Answer: -5.5
Step-by-step explanation:
Answer:
81%
Step-by-step explanation:
Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.
Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:
F = 100% - 19% = 81%
Answer:
Step-by-step explanation:
Hello!
You have two random samples obtained from two different normal populations.
Sample 1
n₁= 15
X[bar]₁= 350
S₁= 12
Sample 2
n₂= 17
X[bar]₂= 342
S₂= 15
At α: 0.05 you need to obtain the p-value for testing variances for a one tailed test.
If the statistic hypotheses are:
H₀: σ₁² ≥ σ₂²
H₁: σ₁² < σ₂²
The statistic to test the variances ratio is the Stenecor's-F test. 
~
The p-value is:
P(
≤0.64)= 0.02
I hope it helps!
