Question Completion:
How are the percentages distributed? Is the distribution skewed? Are there any gaps? (Select all that apply.)
Answer:
1. The percentages are concentrated from 20% to 60%.
2. These data are strongly skewed left.
3. There are no gaps in the data.
Step-by-step explanation:
1. Data
Percentage loss of wetlands per state
46 37 36 42 81 20 73 59 35 50
87 52 24 27 38 56 39 74 56 31
27 91 46 9 54 52 30 33 28 35
35 23 90 72 85 42 59 50 49
48 38 60 46 87 50 89 49 67
2. Re-arrangement of
Percentage loss of wetlands per state (in ascending order)
9 20 23 24 27 27 28 30
31 33 35 35 35 36 37 38
38 39 42 42 46 46 46 48
49 49 50 50 50 52 52 54
56 56 59 59 60 67 72 73
74 81 85 87 87 89 90 91
Answer:
14
Step-by-step explanation:
Convert the fraction into a decimal
1/2 = 0.5
Divide
7/0.5 = 14
Answer:
expression a
Step-by-step explanation:
The given expression is 15+0.25(d−1).
let suppose,
15 = a
0.25(d−1) = b
we get a + b
It clearly indicates the given expression is sum of two entities, we can exclude option b and option d.
Now we are left with option a and c, for that we have to evaluate the term b
b = 0.25(d−1) <u>that is the additional amount after d days</u>
Therefore, expression a is correct.
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation
Calculate z-scores for the following random variable and determine their probabilities from standard tables.
x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088
x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912
x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587
x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413
Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36
Answer: 27
Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36
Answer: 27
Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78
Answer: 204
Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150
Answer: 150
