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iren [92.7K]
1 year ago
11

A farmer wants to net at least $10,000/acre on the sale of his 80-acre property. If he allows for a total of 10% for commissions

and closing costs, what should his listing price be per acre? Assume the farmer has no mortgage
Mathematics
1 answer:
lara [203]1 year ago
5 0

Answer:

$11,111.11

Step-by-step explanation:

Net Money farmer wanted to get the on selling 1 acre = $10,000

Percentage of commission and closing cost incurred by him = 10%

out of 100 %, he will incur cost of 10%,

rest of them will be with him.

In percentage money he would have be = (100 - 10)% = 90%

Thus, 90 % will be net money he would have.

Let the list price be $x

Given that 90% of this $x will be with farmer which is equal to

90% of x = 90/100 * x = 0.9 x

It is given that he wants to net $10000

so 0.9x = $10,000

=> x =  $10,000/0.9 = $11,111.11.

Listing price per acre should be at least  $11,111.11.

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Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
Katarina [22]

Answer:

2x+178\geq 2000

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. x+(x+178)\geq 2000

i.e. 2x+178\geq 2000

Thus, the required inequality is 2x+178\geq 2000.

4 0
2 years ago
You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In
alexandr1967 [171]
C.  $360


$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)
4 0
2 years ago
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Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the
S_A_V [24]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

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3 0
1 year ago
Solve 4/x-4=x/x-4-4/3 for x and determine if the solution is extraneous or not
4vir4ik [10]

<u>Answer:</u>

x = 4 (extraneous solution)

<u>Step-by-step explanation:</u>

\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back x=4, we will get two fractions with zero denominator which would be undefined.

7 0
1 year ago
What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4
valkas [14]
Hi there!

5k - 2k = 12
Solve for K
3k = 12
Divide both sides by 3
3k/3 = 12/3
k = 4
The correct answer is : 4


I hope that helps!
Brainliest answer :)
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