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iren [92.7K]
2 years ago
11

A farmer wants to net at least $10,000/acre on the sale of his 80-acre property. If he allows for a total of 10% for commissions

and closing costs, what should his listing price be per acre? Assume the farmer has no mortgage
Mathematics
1 answer:
lara [203]2 years ago
5 0

Answer:

$11,111.11

Step-by-step explanation:

Net Money farmer wanted to get the on selling 1 acre = $10,000

Percentage of commission and closing cost incurred by him = 10%

out of 100 %, he will incur cost of 10%,

rest of them will be with him.

In percentage money he would have be = (100 - 10)% = 90%

Thus, 90 % will be net money he would have.

Let the list price be $x

Given that 90% of this $x will be with farmer which is equal to

90% of x = 90/100 * x = 0.9 x

It is given that he wants to net $10000

so 0.9x = $10,000

=> x =  $10,000/0.9 = $11,111.11.

Listing price per acre should be at least  $11,111.11.

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On a coordinate plane, 2 exponential functions are shown. f (x) approaches y = 0 in quadrant 2 and then increases into quadrant
strojnjashka [21]

Answer:

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2 years ago
How many intersections are there of the graphs of the equations below? One-halfx + 5y = 6 3x + 30y = 36 none one two infinitely
Sergeu [11.5K]

Answer:

infinitely many

Step-by-step explanation:

You have the system

(1/2)x + 5y = 6

  3x  + 30y = 36

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4 0
2 years ago
Read 2 more answers
From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that ag
Jlenok [28]

Answer:

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.      

Step-by-step explanation:

1) Data given and notation      

\bar X=18.1 represent the mean age when smokers first start to smoke varies  

s=1.3 represent the standard deviation for the sample  

\sigma=2.1 represent the population standard deviation  

n=37 sample size      

\mu_o =5.7 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean starting age is at least 19, the system of hypothesis would be:      

Null hypothesis:\mu\geq 19      

Alternative hypothesis:\mu < 19      

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:      

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

z=\frac{18.1-19}{\frac{2.1}{\sqrt{37}}}=-2.607      

Calculate the P-value      

Since is a one-side lower test the p value would be:      

p_v =P(z  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.      

4 0
2 years ago
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