Let us say that:
o = cost of oranges per pound
p = cost of pears per pound
so that:
o = p – 2
Therefore:
10o + 8p = 61
10 (p – 2) + 8p = 61
10p – 20 + 8p = 61
18p = 81
p = 4.5
p = $4.5 per pound
So 3 pounds of pears would cost:
total cost = 3 * 4.5
total cost = $13.5
We can start solving this problem by first identifying what the elements of the sets really are.
R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.
Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).
W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.
W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.
R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.
0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.
∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are <u>not</u> an element of R).
{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be <u>equal</u> to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).
-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
The first one is; BC
The second one is; Reflection
The third one is; A
The fourth one is; Length
Jalen has total 63 comic books.
Step-by-step explanation:
Given,
Total value of comic books = $3135
Let,
Number of $45 comic books = x
Number of $65 comic books = y
According to given statement;
45x+65y=3135 Eqn 1
x=y+33 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 110

Putting y=15 in Eqn 2

Total comic books = x+y
Total comic books = 48+15 = 63
Jalen has total 63 comic books.
Keywords: addition, elimination method
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