![\sqrt[7]{(7x^3y^2)^{2} } = \sqrt[7]{(49x^6y^4)}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%287x%5E3y%5E2%29%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%5B7%5D%7B%2849x%5E6y%5E4%29%7D%20)
In a fractional exponent the denominator tells what root it is (7th root in this case) and the numerator tells what the value in the parenthesis is raised to (2nd power in this case)
Answer:
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Step-by-step explanation:
Intern No. of Breast
Number Exams Performed X²
1 30 900
2 40 1600
3 8 64
4 20 400
5 26 676
6 35 1225
7 35 1225
8 20 400
9 25 625
<u>10 20 400 </u>
<u> </u><u> ∑ 259 ∑ 7515</u>
Mean= X`= ∑x/n= 259/10= 25.9
Variance = s²= 1/n-1[∑X²- (∑x)²/n]
= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]
= 806.9/9=89.655= 89.66
Standard Deviation= √89.655= 9.4687
Hence
The value of t with significance level alpha= 0.05 and 9 degrees of freedom is t(0.025,9)= 2.262
The 95 % Confidence interval is given by
x`±t(∝,n-1) s/√n
So Putting the values
25.9± 2.262( 9.4687/√10)
= 25.9 ±2.262 (2.9943)
= 25.9 ± 6.7730
= 25.9 +6.7730=32.6730
25.9 -6.7730= 19.1269
= 19.1269, 32.6730
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Answer:
Step-by-step explanation:
Since a large ice chest holds the water = 62 liters
And smaller chest holds the water =
of the larger ice chest
= 
=
liters
Therefore, fraction that represents the amount of ice water in the smaller ice chest will have 0 in the first box, 248 in the numerator and 5 in the denominator.

Answer:
<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>
Step-by-step explanation:
Annual interest rate is 2.75%. Hence, the monthly interest rate is 
The amount will be compounded
times.
Every month they deposits $500.
In the first month that deposited $500 will be compounded 240 times.
It will be ![500\times [1 + \frac{2.75}{1200} ]^{240}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D)
In the second month $500 will be deposited again, this time it will be compounded 239 times.
It will give ![500\times [1 + \frac{2.75}{1200} ]^{239}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D)
Hence, the total after 20 years will be ![500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D%20%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D%20%2B%20........%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B1%7D%20%3D%20160110.6741)
To answer this we would need the expressions given.