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2 years ago

Which equation has only one solution?

1 answer:

6 0

Absolute value cannot be less than 0
Solve Absolute Value.|x−5|=−1No solutions.

|−6−2x|=8
x=−7 or x=1

|5x+10|=10
x=0 or x=−4

|−6x+3|=0
 $x = \frac{1}{2}$

So your answer is D) |–6x + 3| = 0

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A fitted multiple regression equation is Y = 28 + 5X1 - 4X2 + 7X3 + 2X4. When X1 increases 2 units and X2 increases 2 units as w

ad-work [718]

Answer:

A. Increase by 2

Step-by-step explanation:

Given that a fitted multiple regression equation is

$Y = 28 + 5X_1 -4X_2 + 7X_3 + 2X_4$

This is a multiple regression line with dependent variable y and independent variables x1, x2, x3 and x4

The coefficients of independent variables represent the slope.

In other words the coefficients represent the rate of change of y when xi is changed by 1 unit.

Given that x3 and x4 remain unchanged and x1 increases by 2 and x2 by 2 units

Since slope of x1 is 5, we find for one unit change in x1 we can have 5 units change in y

i.e. for 2 units change in x1, we expect 10 units change in Y

Similarly for 2 units change in x2, we expect -2(4) units change in Y

Put together we have

$10-8 =2$ change in y

Since positive 2, there is an increase by 2

A. Increase by 2

5 0

2 years ago

Omar has a gift card for $25 at a clothing store. He wants to buy socks that costs $4 per pair. He also has a coupon for $5 off

bezimeni [28]

Answer:

p= 7 socks

Step-by-step explanation:

gift card:$25

socks:$4

p = 7

4 0

1 year ago

Heidi is saving for a new bike. She has already saved $57. If Heidi earns

PtichkaEL [24]

Answer:

8 hours

Step-by-step explanation:

57 + 9h = 129

9h = 72

h = 8

7 0

2 years ago

Read 2 more answers

What is the length of leg s of the triangle below?

BaLLatris [955]

Option C is your answer.

a² + b² = c²
4² + s² = (√32)²
16 + s² = 32
s² = 16
s = 4

3 0

1 year ago

Read 2 more answers

The graph shows the solution to the initial value problem y'(t)=mt, y(t0)= -4

Charra [1.4K]

$y'(t)=mt
\\
\\ y=\int {mt} \, dt=m \int{t} \,dt=m \frac{t^2}{2} +C \\ \\y= \frac{mt^2}{2}+C$

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.

$y=at^2+b
\\
\\3=a\times 2^2-2
\\
\\3=4a-2
\\
\\5=4a
\\
\\a= \frac{5}{4} 
\\
\\y=\frac{5}{4} t^2-2 \\ \\y= \frac{m}{2} t^2+C
\\ \\ \frac{m}{2} = \frac{5}{4} 
\\
\\m= \frac{5}{2} 
\\
\\C=-2
\\
\\y(t_0)=-4
\\
\\-4= \frac{5}{4} t_0^2-2
\\
\\ -2= \frac{5}{4} t_0^2
\\
\\ t_0^2=- \frac{8}{5} 
\\
\\t_0=\pm \sqrt{- \frac{8}{5} }$

3 0

2 years ago