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2 years ago

How do I find the nth term of the arithmetic sequence -2,2,6,10

Mathematics

1 answer:

Yakvenalex [24]2 years ago

3 0

Answer:

the answer is 30

Step-by-step explanation: gie the other guy brainliest

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A bike wheel is 26 inches in diameter. What is the bike wheel's diameter in millimeters (1 inch = 25.4 millimeters)?

ruslelena [56]

Answer:

Diameter of wheel in millimetres is 660.4

Step-by-step explanation:

Diameter of wheel in inches = 26

given

1 inch = 25.4 millimeters

multiplying RHS and LHS by 26

26*1 inch = 26*25.4 millimeters

=>26 inch = 660.4 mm.

Thus, diameter of wheel in millimetres is 660.4

3 0

2 years ago

Patricia is separating 16 soccer cards and 22 baseball cards into groups each group have the same number of cards madk and each

Rama09 [41]

We have to find the Greatest Common Factor of 16 and 22.GCF ( 16, 22 ) = 2So the greatest number of cards she can put in each group is 2.16 : 2 = 822 : 2 = 11There will be 8 groups of soccer cards and 11 groups of baseball cards.

3 0

2 years ago

Which relationships have the same constant of proportionality between y and x as in the equation y=1/3x?

Marina CMI [18]

Y and X is urgent answer

4 0

2 years ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$

d) ON the same fashion we want to know the norm of the second derivative of $\gamma$ .

We have that $\gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0)$ so the acceleration is given by $\sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10$

6 0

1 year ago

Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon. Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbo

Svetllana [295]

ENter you name for more info:________________

5 0

2 years ago