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salantis [7]
2 years ago
12

Ivanna is playing a game in which she spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a num

bered slice at random.
This game is this: Ivanna spins the spinner once. She wins $1 if the spinner stops on the number 1, $3 if the spinner stops on the number 2, $5 if the spinner stops on the number 3, and $7 if the spinner stops on the number 4. She loses $8 if the spinner stops on 5 or 6.
Mathematics
1 answer:
saul85 [17]2 years ago
8 0

Answer:

The spinner has 6 equal-sized slices, so each slice has a 1/6 probability of showing up.

I guess that we want to find the expected value in one spin:

number 1: wins $1

number 2: wins $3

number 3: wins $5

number 4: wins $7

number 5: losses $8

number 6: loses $8

The expected value can be calculated as:

Ev = ∑xₙpₙ

where xₙ is the event and pₙ is the probability.

We know that the probability for all the events is 1/6, so we have:

Ev = ($1 + $3 + $5 + $7 - $8 - $8)*(1/6) = $0

So the expected value of this game is $0, wich implies that is a fair game.

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Ratio for 669 and 221
alexandr402 [8]

Hello from MrBillDoesMath!

Answer:

669/221

Discussion:

Ratio of 669 to 221 =  669/221.

Now,  669 = 3 * 223 and 221  = 13 * 17. Note that all numbers involved in the factorizations are distinct primes so nothing cancels out in their ratio. That is,

669/221 can not be reduced further.


Thank you,

MrB

5 0
2 years ago
Read 2 more answers
In a data set with a range of 55.4 to 105.4 and 400 observations, there are 176 observations with values less than 86. Find the
IrinaVladis [17]

<u>ANSWER: </u>

In a data set with a range of 55.4 to 105.4 and 400 observations.86 lies in the 49th percentile.

<u>SOLUTION: </u>

Given, in a data set with a range of 55.4 to 105.4 and 400 observations.

There are 176 observations below the value of 86, and we need to find the percentile for 86.

We know that, percentile formula = \frac{\text {number of observations below the required number}}{\text {total number of observations}} \times 100

Percentile of 86 = \frac{176}{400} \times 100

Since, we cancelled 400 with 100 we get 4 , hence above expression becomes,

=\frac{176}{4} = 49

So, percentile of 86 = 49

Hence, 86 lies in the 49th percentile.  

5 0
2 years ago
Using the midpoint method, find the cross-price elasticity of demand for FedEx and UPS overnight shipping if the price of FedEx
IrinaK [193]

Answer:

Cross price elasticity using midpoint method = 0.56

Step-by-step explanation:

Using the mid-point method

Cross-price Elasticity of Demand = <u>% change in Quantity demanded of UPS</u>

                                                          % change of price of FedEx

%change in Quantity demanded of UPS

using Mid-point method                          = <u> Q2-Q1           </u>  × 100

                                                                     (Q1+Q2)÷ 2

                                      = <u>1.3-1.2           </u>   × 100

                                        (1.2+1.3)÷2

                                     = <u>0.1      </u> × 100

                                       1.25

                                     = 8%

% change in price of FedEx

using midpoint method    =<u> P2-P1            </u>× 100

                                             (P1+P2)÷ 2

                                          =<u> 75-65           </u>× 100

                                            (65+75)÷2

                                          =<u> 10  </u>   × 100

                                             70

                                          = 14.28%

Cross-price Elasticity of Demand =  8% ÷ 14.28%

using midpoint method                = 0.56

             

6 0
2 years ago
Freshmen and Sophomores Solve by setting up a system of linear equations with 2 variables and 2 unknowns. A total of 1,595 first
VMariaS [17]

Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595   (1)
s + 15 = r      (2)

Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595  Combine like terms
2s + 15 = 1595      Subtract 15 from both sides
2s = 1595 - 15    
2s = 1580              Divide by 2
s = 1580/2
s = 795 sophmores.

s + r = 1595
795 + r = 1595     Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen

Answer C <<<<<<
8 0
2 years ago
Read 2 more answers
Aseem and Stana are building model cars. Stana's car is 5 less than 2 times the length of Aseem's car. The sum of the lengths of
Ierofanga [76]

Answer:

1. 2x - 5 + x = 20

Step-by-step explanation:

Let Aseem's car as x,

Stana's = 5 less than 2x

= 2x - 5

Aseem's + Stana's = 20

x + 2x - 5 = 20

2x - 5 + x = 20

7 0
2 years ago
Read 2 more answers
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