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m_a_m_a [10]
2 years ago
15

Round 691 to 1 significant figure!

Mathematics
2 answers:
Trava [24]2 years ago
6 0
Rounding to 1 significant figure means writing the number with only 1 non-zero figure.

Thus rounding 691 to 1 significant figure, means writing 691 as 700.


Answer: 700


Remark: if we were asked to round to 2 significant figure, we would round the number as 690
Sedaia [141]2 years ago
5 0

The correct answer is: 700

Explanation:

In order to round to 1 significant figure, ALWAYS REMEMBER, we will look at the first digit of the number, and make sure that it is not zero (zero case will be discussed at the end, as in this particular example zero is not the first digit).

In 691, the first digit at hundredth place is 6. Now we will look at the next digit. In this case, the next digit is 9, which is greater than 5, therefore, the 6 will round off to 7, and rest of the digits will become zero to round it off to one significant figure. Hence, the answer is 700.

(EXTRA INFORMATION) Zero case:

If we have the following number: 0.951. Now the first digit is 0, but as there is a decimal point after that, therefore, it is insignificant. We will move on to the first digit after the decimal point, which is 9 in this case. Now, we will look at the next number. In this case it is 5, therefore, 0.951 is closer to 1.0 after rounding off. Hence, in this case the answer will be 1.0.

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Y = 5.5x is a linear equation (i.e. the highest power of the variables is 1). Therefore, the line will be a straight line with a slope of 5.5
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Follow this link to view Jamie’s work. Critique Jamie’s work by explaining the reasonableness of the scenario and the accuracy o
Stella [2.4K]

Answer:

See  below

Step-by-step explanation:

This graph could describe a relay race.

Jamie writes a scenario that can be modeled by the piecewise function on the graph.

The graph has time, in minutes on the x-axis and the distance, in miles on the y-axis.

The first part of the graph is the line starting from the origin through to the point (12, 1) then the second part starts from the point (12, 1) and ends on the point (20, 2).

1. A runner begins the race and runs at a steady pace for 1 minute.

  • This is incorrect as describes the wrong axis.

It should say: a runner begins a race and runs at a steady pace for 12 minutes, completing 1 mile distance.

<u>The equation for this part:</u>

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  • b = 0 as it starts at origin.
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  • x = [0, 12], y = [0, 1]

2. His partner then takes over and runs at a steady, but faster, pace for another 1 minute.

  • Again, as above, wrong axis is described.

It should say: his partner then takes over and runs at a steady, but faster, pace for another 8 minutes, completing the last 1 mile of the race.

<u>The equation for this part:</u>

  • b =1, as a starting point
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7 0
2 years ago
9400 dollars is placed in an account with an annual interest rate of 6.25%. To the nearest tenth of a year, how long will it tak
liubo4ka [24]

Answer:

t=64.2\ years

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

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in this problem we have

t=?\ years\\ P=\$9,400\\ A=\$47,100\\r=6.25\%=6.25/100=0.0625

substitute in the formula above

47,100=9,400(1+0.0625t)

solve for t

t=[(47,100/9,400)-1]\0.0625

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6 0
2 years ago
LESSON 1 SESSION 1
denpristay [2]

Answer:

  • <em>Between which two tens does it fall?</em><em> </em><u>Between 25 and 26 tens</u>

<em><u /></em>

  • <em>Between which two hundreds does it fall?</em> <u>Between 2 and 3 hundreds</u>

Explanation:

The place-value chart is:

Hundreds         Tens      Ones

       2                   5             3

<em><u /></em>

<em><u>a)  Between which two tens does it fall? </u></em>

Using the place values you can write 253 = 25 × 10 + 3, i.e. 25 tens and 3 ones.

From that you can write:

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Then, you conclude that 253 is between 25 and 26 tens.

<u><em>b) Between which two hundreds does it fall?</em></u>

Using the same reasoning:

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  • 200 < 253 < 300
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Conclusion: 253 is between 2 hundreds and 3 hundreds.

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