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Usimov [2.4K]
2 years ago
8

In a survey, 15 high school students said they could drive and 15 said they could not. Out of 60 college students surveyed, 30 s

aid they could drive. Micah concluded that if someone is in college, that means the person is more likely to drive. Is Micah’s conclusion correct? Explain
Mathematics
2 answers:
AURORKA [14]2 years ago
7 0

Answer:

Equal numbers in each group drive and don’t drive.

The relative frequency of each is 50%.

There is no association between the variables.

Step-by-step explanation:

Alborosie2 years ago
3 0
<span>No, Micah is not correct. Since there are equal numbers of people in each group who drive and who do not drive, the relative frequency for each is 50%. Because the relative frequencies are the same, there is no association between the variables.</span>
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Carly owns a T-shirt shop. She pays $2.25 for each shirt.
diamong [38]

Answer:

Total number of T-shirts= 200

Cost per T-shirt (without shipping ) = $2.80

Shipping cost per t-shirt ; 5% of a T-shirt = 0.05 *2.80 = $0.14

Total cost of T-shirt (shipping included) = 2.80 +0.14 = $2.94

Markup = 150% of total cost = 1.50 * 2.94 = $4.41

To get the price at which Michelle will sell each T-shirt , add total cost  to the markup; 2.94 +4.41 = 7.35.

Therefore, selling price will be $7.35

3 0
2 years ago
0.2x + 0.3y = 1.3.<br>0.4r + 0.5y = 2.3. solve by using substitution ​
Alexxandr [17]

Answer:

x=2, y=3.

Step-by-step explanation:

0.2x + 0.3y = 1.3

0.4x + 0.5y = 2.3

From the first equation   y = (1.3 - 0.2x) / 0.3

Substituting in second equation:

0.4x + 0.5(1.3 - 0.2x) / 0.3 = 2.3

Multiply through by 0.3:

0.12x + 0.5(1.3 - 0.2x) =  0.69

0.12x + 0.65 - 0.1x = 0.69

0.02x = 0.04

x = 2.

Substituting for x in equation 1:

0.2* 2 + 0.3y = 1.3

0.4 + 0.3y = 1.3

0.3y = 1.3 - 0.4 = 0.9

y = 3.

Check in equation 2:

0.4 * 2 + 0.5(3) =   0.8 + 1.5 = 2.3.

- Correct.

4 0
2 years ago
The oblique rectangular prism below has a length of 6 cm, a width of 8 cm, and a height of 7 cm.What is the area of the base of
Rudiy27

Answer:

Area of the base of the prism = 48cm²

Step-by-step explanation:

A rectangular prism has a rectangular base

Area of a rectangular base, A = length x width

A = 6cm x 8cm = 48cm²

5 0
2 years ago
Read 2 more answers
What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4) and D(5,2)?
Dmitry_Shevchenko [17]
I think its going to be around B or D
6 0
2 years ago
Read 2 more answers
Two samples each of size 20 are taken from independent populations assumed to be normally distributed with equal variances. The
Harlamova29_29 [7]

Answer:

t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923

The degrees of freedom are

df=20+20-2=38

And the p value is given by:

p_v =2*P(t_{38}>2.923) =0.0058

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

The system of hypothesis on this case are:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

We have the following data given:

n_1 =20 represent the sample size for group 1

n_2 =20 represent the sample size for group 2

\bar X_1 =43.5 represent the sample mean for the group 1

\bar X_2 =40.1 represent the sample mean for the group 2

s_1=4.1 represent the sample standard deviation for group 1

s_2=3.2 represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

\S^2_p =\frac{(20-1)(4.1)^2 +(20 -1)(3.2)^2}{20 +20 -2}=13.525

And the deviation would be just the square root of the variance:

S_p=3.678

The statistic is givne by:

t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923

The degrees of freedom are

df=20+20-2=38

And the p value is given by:

p_v =2*P(t_{38}>2.923) =0.0058

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

6 0
2 years ago
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