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2 years ago

Round to the nearest ten thousand 905154

1 answer:

5 0

You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:

905,154

 To round 905,154 to the nearest ten-thousands place...

 The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.

 Since the 5 is greater than or equal to 5, we'll round our number up by

 Adding 1 to the 0 in the ten-thousands place, making it a 1.

 and by changing all digits to the right of this new 1 into zeros.

The result is: 910,000.

So, 905,154 rounded to the ten-thousands place is 910,000.

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What is the domain of y = log Subscript 4 Baseline (x + 3)?

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Answer:

All real numbers greater than -3

Step-by-step explanation:

The domain of a log is the baseline is greater than 0.

Set x + 3 greater than zero and solve

x + 3 > 0

x > -3

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Triangle Q R S is shown. Angle Q R S is a right angle. Angle R S Q is 30 degrees and angle S Q R is 60 degrees. The length of R

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The value of sin(30°) is: One-half ⇒ 2nd answer

Step-by-step explanation:

In a right triangle there are two acute angles, the side opposite to the right angle is called hypotenuse, and the other two sides are opposite and adjacent to the acute angles

sine the acute angle (sin) = opposite side to it/hypotenuse
cosine the acute angle (cos) = adjacent side to it/hypotenuse
Tangent the acute angle (tan) = opposite side to it/adjacent side to it

In Δ QRS:

∵ m∠QRS = 90°

∵ SQ is opposite to ∠QRS

∴ SQ is the hypotenuse

∵ SQ = 10 units

∴ The hypotenuse = 10

∵ m∠RSQ = 30°

- The opposite side to ∠RSQ is RQ

∵ RQ = 5 units

∴ The opposite side to the angle of 30° = 5

∵ sin(30°) = opposite side to 30°/hypotenuse

∵ The opposite side to angle 30° = 5

∵ The hypotenuse = 10

∴ sin(30°) = $\frac{5}{10}$

∴ sin(30°) = $\frac{1}{2}$

The value of sin(30°) is: One-half

Learn more:

You can learn more about the trigonometry ratios in brainly.com/question/9880052

#LearnwithBrainly

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I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th

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Answer:

The number of once is 9.1

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18 .........1

100 × H + 1 × O = 900 ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴ H = $\frac{882}{99}$

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e O = 18 - 8.9

∴ O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1 and The number of hundreds is 8.9

Answer

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2 years ago