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2 years ago

If hair grows at a rate of approximately 0.44 mm per day, how many

Mathematics

2 answers:

ale4655 [162]2 years ago

8 0

Answer:

Step-by-step explanation:

40/.44

Agata [3.3K]2 years ago

6 0

Answer:

It would take 90.9 days

Step-by-step explanation:

The sample of the hair considered grows at 0.44mm per day, thus;

0.44mm = 1 day

40 mm = x days

So that, by appropriate deductions,

0.44 × x = 40 × 1

0.44x = 40

Divide both side by 0.44 to determine the value of x;

x = $\frac{40}{0.44}$

x = 90.9090909091

Therfer, it would take up to 90.9 days for the hair to measure 40mm from its follicle to tip.

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Which of the following expressions represents "no more than 5"?

777dan777 [17]

Answer:

Ox>5

x is less than 5

means nothing more than 5 but anything less than 5

5 0

2 years ago

Carlo used this number line to find the product of 2 and −3. A number line going from negative 7 to positive 3. An arrow goes fr

Vesnalui [34]

Answer:

The errors are;

a. negative 4 to negative 6

b. negative 2 to negative 4

Step-by-step explanation:

The number line is the mathematical representation of numbers in the horizontal line or the x-axis.

The result of the multiplication of a positive 2 and a negative 3 is;

2 x -3 = -6 , gives a negative 6.

So the number line should scale to accommodate the operands and the result, which is from negative 7 to positive 3, in the option given.

8 0

2 years ago

If a watch store paid $125 per watch for a shipment of watches, and sold all but 15 watches from the shipment for $150 per watch

yan [13]

Answer: C) P(y) = 150(y – 15) – 125y

Step-by-step explanation:

Hi, to answer this question we have to write an equation:

Profit = revenue - cost

Cost: a watch store paid $125 per watch for a shipment of watches

Cost = 125 y

Where y is the number of watches in the shipment

Revenue: sold all but 15 watches from the shipment for $150 per watch

Revenue = 150(y-15)

Profit(y) = 150(y – 15) – 125y

So, the correct option is:

C) P(y) = 150(y – 15) – 125y

Feel free to ask for more if needed or if you did not understand something.

8 0

2 years ago

Resource Allocation You manage an ice cream factory that makes two flavors: Creamy Vanilla and Continental Mocha. Into each quar

vovikov84 [41]

Answer:

in order to use up all the eggs and cream, the number of quarts of each flavor that should be made is;

Creamy vanilla x = 200 quarts

Continental mocha y = 100 quarts

Step-by-step explanation:

Let x and y represent the number of quarts of Creamy Vanilla and Continental Mocha that should be made in order to use up all the eggs and cream respectively.

For Creamy Vanilla go 2 eggs and 3 cups of cream

For Continental Mocha go 1 egg and 3 cups of cream.

Total number of eggs = 500 eggs

Total number of cream cups = 900 cups.

For the eggs;

2 eggs × x + 1 egg × y = 500

2x + y = 500 .......1

For the cream cups;

3 cups × x + 3 cups × y = 900

3x + 3y = 900

Dividing through by 3

x + y = 300 .......2

Solving the simultaneous equation;

Subtracting equation 2 from 1

(2x + y) - (x+y) = 500-300

2x -x = 200

x = 200

Substituting x = 200 into equation 2;

200 + y = 300

y = 300 - 200

y = 100

Therefore, in order to use up all the eggs and cream, the number of quarts of each flavor that should be made is;

Creamy vanilla x = 200 quarts

Continental mocha y = 100 quarts

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2 years ago

Decide whether the set A of positive integers divisible by 17 and B the set of positive integers

murzikaleks [220]

Answer:

Yes; see clarification of the question and the complete answer explained answer below.

Explanation:

Two sets are in bijection if the function that relates them is bijective.

Thus, the question may be reformulated to: is it possible that the two sets A and B are related by a bijective function?

A bijective function is both inyective and surjective, which implies that it is invertible.

Inyective means that any element of the domain is mapped into exactly one element of the codomain.

Surjective means that each element of the codoman is related exactly with one element of the codomain.

That implies that there are no unpaired elements.

Assume the set A is the domain of your function and B is the codomain.

Then, the question is: is it possible for the set {17, 34, 51, 68, 85, . . .} to be in bijection with the set {11, 22, 33, 44, 55, . . . }?

Realize the two sets do not have common elements, because 17 and 34 are relative primes.

It is possible to set a bijective function of A onto B, or of B onto A, if and only if the two sets have the same cardinality (number of elements).

Indeed, the two sets A and B have the same cardinality: both have the same size, thus you may conclude that there could be a bijection relation between them and thus the two sets are in bijection.

4 0

2 years ago