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vodomira [7]
2 years ago
12

Which system of equations can be used to find the roots of the equation 12 x cubed minus 5 x = 2 x squared + x + 6? StartLayout

Enlarged left-brace 1st Row y = 12 x cubed minus 5 x 2nd row y = 2 x squared + x + 6 EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed minus 5 x + 6 2nd row y = 2 x squared + x EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed + 2 x squared minus 4 x 2nd row y = 6 EndLayout StartLayout Enlarged left-brace 1st Row y = 12 x cubed + 2 x squared minus 4 x + 6 2nd row y = 0 EndLayout
Mathematics
1 answer:
OverLord2011 [107]2 years ago
7 0

Answer:

A

Step-by-step explanation:

12x³-5x=2x²+x+6

y=12x³-5x

y=2x²+x+6

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Which of the following are possible explicit formulas for the nth term of the constant velocity sequence below? Check all that a
oksano4ka [1.4K]
We have an arithmetic progression:
Nth=an
an=a₁+(n-1)d
a₁ is the first term.
n=number of terms.
d=common difference

10,17,24,31...
a₁=10
d=a₂-a₁=17-10=7

Therefore:
Nth=an
an=a₁+(n-1)d
an=10+(n-1)7
an=10+7n-7
an=7n+3.

Therefore: the formula for the nth is, an=a+(n-1), in this case; an=7n+3,

To check:
a₁=7*1+3=10
a₂=7*2+3=17
a₃=7*3+3=24
a₄=7*4+3=31
a₅=7*5+3=38.......
8 0
2 years ago
At summer camp the ratio of boys to girls was 7:2 If there were 21 boys how many girls were there?
Alenkinab [10]
Ratio:\\7:2\\\\
7x-number\ of\ boys\\2x-number\ of\ boys\\\\
7x=21\ \ \ |:7\\
x=3\\\\
2x=2*3=6\\
Number\ of\ girls\ is\ equal\ to\ 6.
3 0
2 years ago
What is the value of 6i/1+i? 2 – 6i 2 + 6i 3 – 3i 3 + 3i
mihalych1998 [28]

6i/ (1+i)  

multiply by the complex conjugate (1-i)/(1-i)

6i/(1+i) *  (1-i)/(1-i)

6i* (1-i) = 6i - 6i^2 = 6i - 6(-1) = 6i +6

(1+i)*(1-i)= 1-i +i -i^2 = 1 -i+i -(-1) = 1+1=2

(6+6i)/2

3+3i

Answer: 3+3i

6 0
2 years ago
Read 2 more answers
When plucked, the high E string on a guitar has a frequency of 330 cycles per second. What sine function represents this note wh
Ber [7]

Let's analyse the function

y = f(x) = A\sin(\omega x)

The amplitude is A, so we want A=1.5

Now, we start at x=0, and we have 1.5\sin(0)=0

After one second, i.e. x=1, we want this sine function to make 330 cycles, i.e. the argument must be 330\cdot 2\pi

So, we have

f(1)=1.5\sin(\omega) = 1.5\sin(660\pi)

so, the function is

f(x) = 1.5\sin(660\pi x)

4 0
2 years ago
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Which option lists an expression that is not equivalent to 4 2/3?
I am Lyosha [343]

Answer:

Option A and Option B are not equivalent to the given expression.

Step-by-step explanation:

We are given the following expression:

4^{\frac{2}{3}}

Applying properties of exponents and base:

(a^x)^y = a^{xy}\\a^{-x}= (\frac{1}{a})^x\\

A. Using the exponential property a^{-x}= (\frac{1}{a})^x\\, we can write:

0.25^{\frac{3}{2}} = (\frac{1}{0.25})^{\frac{-3}{2}} = (4)^{\frac{-3}{2}}

which is not equal to the given expression.

B. Using the exponential property a^{-x}= (\frac{1}{a})^x\\, we can write:

(0.25)^{\frac{-3}{2}} = (\frac{1}{0.25})^{\frac{3}{2}} = (4)^{\frac{3}{2}}

which is not equal to the given expression.

C. First we convert the radical form into exponent form. Then by using the property (a^x)^y = a^{xy} of exponent, we can write the following:

^3\sqrt{16} = (16)^{\frac{1}{3}} = (4^2)^{\frac{1}{3}} = 4^{\frac{2}{3}}

which is equal to the given expression.

D. First we convert the radical form into exponent form. Then by using the property (a^x)^y = a^{xy} of exponent, we can write the following:

(^3\sqrt{4})^2 = (4^{\frac{1}{3}})^2 = 4^{\frac{2}{3}}

which is equal to the given expression.

Option D and Option C are equivalent to the given expression.

7 0
2 years ago
Read 2 more answers
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