Answer:
Given: A triangle ABC and a line DE parallel to BC.
To prove: A line parallel to one side of a triangle divides the other two sides proportionally.
Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have
∠A=∠A (Common)
∠ADE=∠ABC (Corresponding angles)
Thus, by AA similarity, ΔABC is similar to ΔADE, therefore
AB/AD= AC/AE
⇒AD+DB/AD = AE+EC/AE
⇒1+DB/AD = 1+ EC/AE
⇒DB/AD = EC/AE
Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.
⇒Therefore Proved
Hope this helps!!!
Answer is r32 because it is the square root of an exponent you must divide it.
Answer:
g(x) = RootIndex 3 StartRoot x + 2 EndRoot
Level, x 1 0.8 0.65
time, y 0 1 2
The graph is not a straight line, it is curved. You can observe this only if you include the point (1,0), which is the level at the begining (100%)
The y - intercept is the full level, at the beginning of the experiment.