What is the 12th partial sum of the summation of negative 2i minus 10, from i equals 1 to infinity?
1 answer:
Ans: 12th partial sum = -276
Given :
Find the values for i = 1 to 12:
x (1) = -2 – 10 = -12
x (2) = -4 – 10 = -14
x (3) = -6 – 10 = -16
x (4) = -8 – 10 = -18
x (5) = -10 – 10 = -20
x (6) = -12 – 10 = -22
x (7) = -14 – 10 = -24
x (8) = -16 – 10 = -26
x (9) = -18 – 10 = -28
x (10) = -20 – 10 = -30
x (11) = -22 – 10 = -32
x (12) = -24 - 10 = -34
Add all of them:
12th partial sum = -276
Given :
Find the values for i = 1 to 12:
x (1) = -2 – 10 = -12
x (2) = -4 – 10 = -14
x (3) = -6 – 10 = -16
x (4) = -8 – 10 = -18
x (5) = -10 – 10 = -20
x (6) = -12 – 10 = -22
x (7) = -14 – 10 = -24
x (8) = -16 – 10 = -26
x (9) = -18 – 10 = -28
x (10) = -20 – 10 = -30
x (11) = -22 – 10 = -32
x (12) = -24 - 10 = -34
Add all of them:
12th partial sum = -276
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Answer: $2193
Step-by-step explanation:
v(x) = 32,500
Plug two and three in for x
v(2) = 32,500
v(2) = 32,500(.8464)
v(2) = 27,500
v(3) = 32,500
v(3) = 32,500(.778688)
v(3) = 25,307.36
Subtract v(3) from v(2)
27,500 - 25,307.36 = 2192.64
Round to the nearest dollar to get $2193
Answer:
It does because 26 = 20 + 6, and the model shows 2 groups of 10 and 2 groups of 3.
Step-by-step explanation:
Two groups of 10 make 20. Two groups of 3 make 6.
20 + 6 = 26
B is wrong. The model does not show two groups of 6.
C is wrong. The model should show one group of 6..
D is wrong. The model should show two groups of 10 and one group of 6.
