How to write eight ten-thousandths of thirty-five million in scientific notation?

Sam's Furniture Store places the following advertisement in the local

Dmitry [639]

Answer:

1. The system of equations is given as follows;

S + L = $1,300................(1)

S + 2·C = $1,400............(2)

S + L + C = $1,600.........(3)

Where;

S = The cost of a sofa

L = The cost of a love sea

C = The cost of a single chair

2. The cost of a love sea, L is $500

Step-by-step explanation:

1. The given information are;

The price of sofa and love sea = $1,300

The price of sofa and two chairs = $1,400

The price of sofa, love sea, and one chair = $1,600

Let the cost of a sofa = S

Let the cost of a love sea = L

Let the cost of a chair = C

Therefore, we have;

S + L = $1,300................(1)

S + 2·C = $1,400............(2)

S + L + C = $1,600.........(3)

2. From equation (1), we have;

L = $1,300 - S

Similarly, from equation (2),we have;

C = ($1,400 - S)/2

Substituting the values of L and C in equation (3), we have;

S + $1,300 - S + ($1,400 - S)/2 = $1,600

Which gives;

($1,400 - S)/2 = $1,600 - $1,300 = $300

$1,400 - S = 2 × $300 = $600

$1,400 = $600 + S

$600 + S = $1,400

S = $1,400 - $600 = $800

S = $800

The cost of a love seat, L, is given from the relation L = $1,300 - S, above, which gives;

L = $1,300 - $800 = $500

The cost of a love sea, L is $500 .

8 0

1 year ago

What is the unit price of 8 mugs for $38.32

jarptica [38.1K]

Answer:

4.79$ for each mug

Step-by-step explanation:

38.32/8 = 4.79 and to double-check do 4.79*8

8 0

1 year ago

Read 2 more answers

Jason states that -5.0 is not an integer because it is a decimal. Is he correct? Why or why not?

gulaghasi [49]

Answer:

The answer is No, he's incorrect

Step-by-step explanation:

Because -5.0 is still -5 so therefore it makes -5.0 an integer

5 0

1 year ago

A university warehouse has received a shipment of 25 printers, of which 10 are laser printers and 15 are inkjet models. If 6 of

Tanya [424]

Answer:

The probability is 0.31

Step-by-step explanation:

To find the probability, we will consider the following approach. Given a particular outcome, and considering that each outcome is equally likely, we can calculate the probability by simply counting the number of ways we get the desired outcome and divide it by the total number of outcomes.

In this case, the event of interest is choosing 3 laser printers and 3 inkjets. At first, we have a total of 25 printers and we will be choosing 6 printers at random. The total number of ways in which we can choose 6 elements out of 25 is $\binom{25}{6}$ , where $\binom{n}{k} = \frac{n!}{(n-k)!k!}$ . We have that $\binom{25}{6} = 177100$

Now, we will calculate the number of ways to which we obtain the desired event. We will be choosing 3 laser printers and 3 inkjets. So the total number of ways this can happen is the multiplication of the number of ways we can choose 3 printers out of 10 (for the laser printers) times the number of ways of choosing 3 printers out of 15 (for the inkjets). So, in this case, the event can be obtained in $\binom{10}{3}\cdot \binom{15}{3} = 54600$

So the probability of having 3 laser printers and 3 inkjets is given by

$\frac{54600}{177100} = \frac{78}{253} = 0.31$

4 0

2 years ago

An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They

arlik [135]

Answer:

So on this case the 90% confidence interval would be given by $-4.137 \leq \mu_1 -\mu_2 \leq 2.087$

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =2.0233$ represent the sample mean 1

$\bar X_2 =3.048$ represent the sample mean 2

n1=15 represent the sample 1 size

n2=15 represent the sample 2 size

$s_1 =4.893387$ population sample deviation for sample 1

$s_2 =5.12399$ population sample deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: $\mu_1 = \mu_2$

H1: $\mu_1 \neq \mu_2$

And we can do this using the confidence interval for the difference of means.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 15+15-2=28$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that $t_{\alpha/2}=\pm 1.701$

Now we have everything in order to replace into formula (1):

$-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137$

$-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087$

So on this case the 90% confidence interval would be given by $-4.137 \leq \mu_1 -\mu_2 \leq 2.087$

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

4 0

1 year ago