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kherson [118]
2 years ago
7

A proofreader earns $8.50 for each page that he proofreads. If he works 7.5 hours and proofreads 14 pages each day on average, w

hich proportion can be used to calculate his average hourly wage,w?
Mathematics
2 answers:
dimulka [17.4K]2 years ago
7 0

Answer:

$15.8666666667 an hour on average

Step-by-step explanation:

14/7.5=1.8666666666

this means that for every hour the proofreader is working he proof reads 1.8666667 pages since he makes 8.5 for every page we have to multiply the pages per hour times the salary of every page to get his average hourly wage

1.8666666666 * 8.5 = $15.8666666667 an hour on average

Greeley [361]2 years ago
6 0

Answer:

119/7.5 = w/1

Step-by-step explanation:

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Lines AB and CD and are parallel. Find the measures of the three angles in triangle ABF.
Airida [17]

Answer:    ∠B = 42°   ∠A = 23°  ∠F = 115°

Step-by-step explanation:

∠B≅∠C  alternate interior angles  42°

  ∠CDF is supplementary to ∠CDE,

so m∠CDF = 23°  and ∠FAB≅∠CDF so m∠FAB= 23°

<em>also ∠A ≅ CDE  corresponding angles  157° ∠FAB is suplementary to ∠A </em>

<em>so 180 - 157 = 23 gives the m∠FAB</em>

The sum of the angles of a triangle is 180°, so m∠AFB = 180 -(23 +42)

180- 65 = 115 = m∠F

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2 years ago
What is the area of a trapezoid with height 5m and bases 8m and 1m.
tankabanditka [31]
Area of a trapezoid:
A = 1/2 * ( b 1 + b 2) *h
b 1 = 8 m,  b 2 = 1 m,  h = 5 m;
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Answer: B ) 22.5 m²
8 0
2 years ago
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A parachute is descending at a rate of 28 feet per minute. Find the total change in the altitude of the parachute after 4 minute
BigorU [14]

Answer:

The total change in the altitude of the parachute after 4 minutes is 92 ft

Step-by-step explanation:

Here, we want to calculate the total change in the altitude of the parachute.

The rate of change per minute = 28 ft/m

Now in 4 minutes, the total altitude change will be;

28 ft/min * 4 min = 92 ft

In 4 minutes, there would have been a change of 92 ft in the altitude of the parachute

8 0
2 years ago
Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)
UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600

Therefore, the probability is

P=\frac{12117600}{53524680}\\\\P=0.226

b) We calculate the probability that are at least 2 red balls.

We calculate the probability  withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations: for 1 red balls

C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848

Therefore, the probability is

P_1=\frac{16138848}{53524680}\\\\P_1=0.3

We calculate the number of favorable combinations: for none red balls

C_7^{34}=5379616

Therefore, the probability is

P_0=\frac{5379616}{53524680}\\\\P_0=0.1

Therefore, the  the probability that are at least 2 red balls is

P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056

Therefore, the probability is

P=\frac{44056}{53524680}\\\\P=0.0008

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\

Let Y, event that exactly 3 blue balls selected.

P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\

We have

P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12

Therefore, we get

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74

8 0
2 years ago
Lola tossed a coin twice. She made a tree diagram to show the possible outcomes. Which tree diagram shows the sample space for t
trapecia [35]

Answer:

Sample space for two tosses of a coin [HH, TT, HT,TH]

Step-by-step explanation:

Im sorry if you got it wrong :(

please tell me in the comments

8 0
2 years ago
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