The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If
m is the mean number of customers serviced in an hour, then P=1-e^mt
1 answer:
Answer: option d.
Step-by-step explanation:
You have the following formul given in the problem:
You know that:
The number of customers serviced in an hour by the technical support representative is 6 costumbers, therefore:
As the problem asked for the probability that a costumber will be on hold less than 30 minutes, we know that:
Substitute the values above into the formula.
Then, you obtain:
or 95%
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Using the uniform distribution, it is found that:
A,B) 0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.
C) 20% of the time does Josh’s bag arrive in less than 22 minutes.
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An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
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- In the graph, we have that the distribution is uniform between 20 and 30 minutes, thus
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Itens a and b:
- Above 27 minutes, thus:
0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.
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Item c:
- Less than 22 minutes, thus:
0.2*100 = 20%
20% of the time does Josh’s bag arrive in less than 22 minutes.
A similar problem is given at brainly.com/question/15855314