Question

The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If m is the mean number of customers serviced in an hour, then P=1-e^mt

Answer 1

Answer: option d.

Step-by-step explanation:

You have the following formul given in the problem:

$p=1-e^{-mt}$

You know that:

The number of  customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

$m=6$

As the problem asked for the probability that  a costumber will be on hold less than 30 minutes, we know that:

$t=0.5$

Substitute the values above into the formula.

Then, you obtain:

$p=1-e^{-(6)(0.5)}=0.95$ or 95%