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Softa [21]
2 years ago
9

Ravi's age is double Ranu's age. The product of their ages in years is 72. How old is Ranu?

Mathematics
1 answer:
Phoenix [80]2 years ago
6 0
V : Ravi's age
N : Ranu's age

V = 2N
V + N = 72

Input the "V = 2N" into "V + N = 72"

2N + N = 72

Add like terms.

3N = 72

Divide.

N = 24 yrs.

Input N in "V = 2N"

V = 2 ( 24 )

Multiply.

V = 48 yrs.

Ravi is 48 years old and Ranu is 24 years old.


Hope this helped! Good luck! :D
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At a store, apples cost $0.80 $0.80 each and oranges cost $0.95 $0.95 each. Harry buys some apples and oranges and spends $9.55
gregori [183]

Answer:

Harry buys 6 apples and 5 oranges at the store.

Step-by-step explanation:

Given:

Cost of each apples = $0.8

Cost of each oranges = $0.95

Total money spend =$9.55

Number of fruits bought= 11

We need to find the number of apples bought and number of oranges were bought.

Solution:

Let the number of apples bought be 'a'.

Let the number of oranges were bought be 'o'.

Number of fruits bought= 11

So we can say that;

Number of fruits bought is equal to sum number of apples bought and number of oranges were bought.

framing in equation form we get;

a+o=11 ⇒ equation 1

Now we can say that;

Total money spend is equal to number of apples bought multiplied by Cost of each apples plus number of oranges were bought multiplied by Cost of each oranges.

framing in equation form we get;

0.8a+0.95o=9.55 ⇒ equation 2

Now Multiplying equation 1 by 0.8 we get;

0.8(a+o)=0.8\times11

0.8a+0.8o=8.8 ⇒ equation 3

Subtracting equation 3 from equation 2 we get;

0.8a+0.95o-(0.8a+0.8o)=9.55-8.8\\\\0.8a+0.95o-0.8a-0.8o=0.75\\\\0.15o=0.75

Dividing both side by 0.15 we get;

\frac{0.15o}{0.15}=\frac{0.75}{0.15}\\\\o=5

Substituting the value of o in equation 1 we get;

a+o=11\\\\a+5=11\\\\a=11-5=6

Hence Harry buys 6 apples and 5 oranges at the store.

3 0
2 years ago
Students make 93.5 ounces of liquid soap for a craft fair. They put the soap in ​5.5-ounce bottles and sell each bottle for ​$4.
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Answer:

$76.5

Step-by-step explanation:

93.5÷5.5=17

17×4.50=76.5

Therefore the answer is 76.5.

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A certain forest covers an area of 4000 km2. Suppose that each year this area decreases by 7%. What will the area be after 5 yea
Levart [38]
Answer:

2,600

Explanation:

Your first step is to find 7% of 4000 ( this is what it is decreasing by per year).
As a result you end up with 280.
Multiply 280 by 5.
1,400 should be your answer( amount of km decreasing after 5 years). This is a decreasing forest, so you subtract 4,000by 1,400.
8 0
2 years ago
2.4 Backgammon. Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two di
muminat

Answer:

The claim is not fair because:

  • Probability of roliing two 6s = Probability of rolling two 3s = 1/36

Step-by-step explanation:

The <em>probaility</em> of an event is defined as the number of favorable outcomes divided by the number of total possible events.

P (event E) = number of outcomes for event E / number of possible events

1. <u>As </u><u>first step</u><u>, you may draw a table to find the </u><u>sample space</u><u> (set of all possible outcomes)</u>.

<u>Sample space</u>

The results of the rolling two dice are summarized in this table:

                    Second roll    1       2       3       4        5      6

First roll

  1                                       (1,1)  (1,2)    (1,3)   (1,4)   (1,5)  (1,6)

  2                                     (2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

  3                                     (3,1)  (3,2)  <u>(3,3)</u>   (3,4)  (3,5)  (3,6)

  4                                     (4,1)   (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

  5                                     (5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

  6                                     (6,1)  (6,2)  (6,3)  (6,4)  (6,5)  <u>(6,6)</u>

<u></u>

2.<u>Now, in that table, you can observe</u>:

The results (3,3) and (6,6) are highlited.

a) Total number of events: 6 × 6 = 36

b) Nnmber of outcomes for the event rolling two 6s (6,6): 1

c) Number of outcomes for the event rolling two 3s (3,3): 1

3) <u>Next, you can calculate the probabilities:</u>

a) Probability rolling two 6s = 1 / 36

b) Probability of rolling two 3s: 1 / 36

4. <u>Conclusion</u>: the probabilities prove that rolling two 6s is just as likely as rolling two 3s.

7 0
2 years ago
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